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Moose352
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Imagine a rod in space. If I exert a force at one end, will the rod translate, rotate, or both? How do I determine what it will do?
Yes, it would be.Originally posted by Moose352
Okay, if I had a seesaw of 2 kg, which was 10 meters long, with a child (4kg) at each end, then what would be the force exerted on the fulcrum. Would it not be 2g + 4g + 4g?
Say for example one kid weighs 2kg (small kid). Then the balanced force acting on the fulcrum is 2+2+2 and the rotational force (moment) is 2.What would be the force be if the seesaw became to rotate (that is, the net torque is not 0).
In rotational motion, translation refers to the linear movement of an object along a straight path, while rotation refers to the circular movement of an object around a fixed point.
The force on a rod in rotational motion is calculated using the formula F = Iα, where F is the force applied to the rod, I is the moment of inertia of the rod, and α is the angular acceleration.
Torque and force are directly proportional in rotational motion, meaning that an increase in torque will result in an increase in force, and vice versa.
The distribution of mass in an object affects its moment of inertia, which is a measure of the object's resistance to rotational motion. Objects with a greater mass distributed farther from the axis of rotation will have a higher moment of inertia and require more force to rotate.
Friction plays a crucial role in rotational motion by providing a force that opposes the movement of an object, thus slowing down its rotation. This is important in controlling the speed and stability of rotating objects.