Show that the following function is Riemann integrable.

In summary, the conversation discusses how to show that the function f: [0,1] -> R is Riemann integrable on [0,1]. The individual suggests using Cauchy's criterion, but the other person explains that the function can be shown to be Riemann integrable directly from the definition by showing that the lower and upper Riemann sums have a common least upper bound. They also suggest constructing a partition of [0,1] to prove this.
  • #1
cooljosh2k2
69
0

Homework Statement



Show that the function f: [0,1] -> R defined by:

f(x) = 1, if x=1/k for some k
f(x) = 0, else

is Riemann integrable on [0,1]

Homework Equations





The Attempt at a Solution



I attempted the problem using Cauchy's criterion but found that this function is not Riemann integrable, am i right? or am i going about this the wrong way.
 
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  • #2
I'm assuming you don't have access to any of the standard equivalent criteria to Riemann integrability. To show that a function is Riemann integrable directly from the definition, you must show that the lower and upper integral are equal, that is, that the lower and upper Riemann sums have a common least upper (greatest lower) bound.

First of all, by looking at the function, you should be able to see immediately what the lower sums should be and therefore what the value of the integral must be. So you just have to prove that the infimum of the upper sums is the right thing. This you do by constructing, for any [tex]\varepsilon > 0[/tex], a partition of [tex][0,1][/tex] such that the upper sum with respect to this partition differs from the value of the integral by less than [tex]\varepsilon[/tex].
 

FAQ: Show that the following function is Riemann integrable.

What is the definition of Riemann integrability?

Riemann integrability is a property of a function on a closed interval that allows for the calculation of its definite integral. A function is considered Riemann integrable if its upper and lower Riemann sums converge to the same value as the partition of the interval approaches zero.

How do you show that a function is Riemann integrable?

In order to show that a function is Riemann integrable, one must demonstrate that its upper and lower Riemann sums converge to the same value as the partition of the interval approaches zero. This can be done by showing that the function is bounded and discontinuous at a finite number of points, or by using the Riemann integral definition to evaluate the integral.

What is the Riemann integral definition?

The Riemann integral definition states that a function f(x) on a closed interval [a, b] is integrable if and only if, for any given ε > 0, there exists a partition P of [a, b] such that for any refinement P' of P, the difference between the upper and lower Riemann sums of f over P' is less than ε.

Can a function be Riemann integrable on a closed interval if it is not continuous?

Yes, a function can still be Riemann integrable on a closed interval even if it is not continuous. The only requirement for Riemann integrability is that the function is bounded and has a finite number of discontinuities on the interval.

What are some common examples of functions that are not Riemann integrable?

Some common examples of functions that are not Riemann integrable include the Dirichlet function, the Thomae's function, and the Cantor function. These functions have infinite discontinuities on the interval and therefore do not meet the requirements for Riemann integrability.

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