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unfunf22
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Homework Statement
If A is nonsingular, prove that the eigenvalues of A-1 are the reciprocals of the eigenvalues of A.
*Use the idea of similar matrices to prove this.
Homework Equations
det(I[tex]\lambda[/tex] - A) = 0
B = C-1AC (B and A are similar, and thus have the same determinants)
The Attempt at a Solution
At first I showed that A is nonsingular iff 0 is not an eigenvalue of A. To do this I just used the fact that det(A-1) = 1/det(A) and that if lambda was 0, then we'd have det(A) = 0, which would mean A-1 is undefined. If lambda isn't 0, then we have det(I[tex]\lambda[/tex] - A) = 0, which tells us A is nonsingular.
As for the other proof, I'm convinced I have to use the idea of similar matrices, because the book I am using is focusing on them right now, and these exercises are relating to them.
But A-1 and A are not the same linear transformation (unless A = I), so they are not similar. Therefore I cannot use the formula: B = C-1AC
So, I am lost on how to do this proof using the idea of similar matrices. Anyone know how I could accomplish this?
-Ian