Simple 2 level paramagnet system- How to find the number of states

In summary, the problem involves N non-interacting particles in an external magnetic field, with a Hamiltonian given by H = -h\sum^{N}_{i=1}{\sigma_{i}}. The number of states with a given energy E can be calculated using the equation \Omega = \sum^{}_{\sigma}{\delta{(E-H)}} and the integral representation of the delta function. By using the equations E = (N_{up} - N_{down})(- \mu_{B}|\vec{H}|) and N_{up} + N_{down} = N, the number of corresponding configurations can be found as \Omega = \frac{N!}{N_{up}!N_{
  • #1
Uncle_John
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Homework Statement


We have [itex]N[/itex] non interacting particles in external field [itex]\vec{H}[/itex]. The hamiltonian is given as [itex]H = -h\sum^{N}_{i=1}{\sigma_{i}}[/itex] with [itex]\sigma =\pm 1 [/itex] and [itex]h = - \mu |\vec{H}|[/itex]. Calculate the number of states with given energy [itex]E[/itex] with help of this relation:

[itex]\Omega = \sum^{}_{\sigma}{\delta{(E-H)}}[/itex]

where [itex]\sum^{}_{\sigma}[/itex] represent summing over all configurations
Hint: Use Integral representation of delta function. Integrand can be written in form: [itex]exp[N f(k)][/itex]. Make a Taylor approximation of second order with respect to [itex]k[/itex] and solve integral.




Homework Equations


So, integral representation of delta function looks like that:
[itex]\delta(x) = \frac{1}{2\pi}\int^{\infty}_{-\infty}{exp(-ikx)}dx[/itex]

I'm asking for some hints, or advices, my main problem is that I'm not really sure how to handle that summation over all configurations and also, do we really need to play here with this delta function? We know that following is true:

[itex]E = (N_{up} - N_{down})(- \mu_{B}|\vec{H}|)[/itex]

and also [itex]N_{up} + N_{down} = N[/itex]

So if [itex]E[/itex] and [itex]N[/itex] are given, we can find out [itex]N_{up}[/itex]
and [itex]N_{down}[/itex] and from there we know that the number of all (to energy [itex]E[/itex]) corresponding configurations equals:

[itex]\Omega = \frac{N!}{N_{up}!N_{down}!}[/itex]

I'm sure i must be missing something, can someone be so kind and enlighten me:D
 
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  • #2
The Attempt at a Solution So, integral representation of delta function looks like that:\delta(x) = \frac{1}{2\pi}\int^{\infty}_{-\infty}{exp(-ikx)}dxI'm asking for some hints, or advices, my main problem is that I'm not really sure how to handle that summation over all configurations and also, do we really need to play here with this delta function? We know that following is true:E = (N_{up} - N_{down})(- \mu_{B}|\vec{H}|)and also N_{up} + N_{down} = NSo if E and N are given, we can find out N_{up}and N_{down} and from there we know that the number of all (to energy E) corresponding configurations equals:\Omega = \frac{N!}{N_{up}!N_{down}!}I'm sure i must be missing something, can someone be so kind and enlighten me:D
 

FAQ: Simple 2 level paramagnet system- How to find the number of states

What is a simple 2 level paramagnet system?

A simple 2 level paramagnet system is a physical system composed of particles with two possible states, usually referred to as "up" and "down". These particles are subject to a magnetic field, which can influence their respective states.

How do you determine the number of states in a simple 2 level paramagnet system?

The number of states in a simple 2 level paramagnet system can be determined by using the formula 2^n, where n is the number of particles in the system. This means that for a system with 3 particles, there would be 8 possible states.

Can the number of states in a simple 2 level paramagnet system change?

Yes, the number of states in a simple 2 level paramagnet system can change if the number of particles in the system changes. This is because the formula 2^n is dependent on the number of particles in the system.

How does the magnetic field affect the number of states in a simple 2 level paramagnet system?

The magnetic field has no direct effect on the number of states in a simple 2 level paramagnet system. However, it can influence the probability of a particle being in a certain state, as the magnetic field can align the particles in a preferred direction.

Are there any applications of a simple 2 level paramagnet system?

Yes, simple 2 level paramagnet systems have various applications in physics and technology. They can be used to study the behavior of particles in a magnetic field, as well as in data storage devices such as hard drives and magnetic tapes.

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