Size of VY Canismajoris and gravity

  • Thread starter SecretOfnumber
  • Start date
  • Tags
    Gravity
In summary, the smallest known star is OGLE-TR-122b and the biggest star in the universe is Canismajoris VY. Now my question is: what cause these two to be so different in shape? if the gravity is the planer for size, then how VY could become so huge in size before start collapsing?what volume of gas setup to create such a monster?!
  • #1
SecretOfnumber
20
0
Smallest known star is OGLE-TR-122b and the biggest star in the universe is Canismajoris VY , now my question is :
what cause these two to be so different in shape? if the gravity is the planer for size, then how VY could become so huge in size before start collapsing?what volume of gas setup to create such a monster?!

Thanks
 
Astronomy news on Phys.org
  • #2
Stable stars are in an equilibrium of pressure (outwards) and gravity (inwards). Pressure is mainly radiation pressure and comes from the release of energy in the core (due to fusion). Heavier stars release more energy, so they tend to have a higher radiation pressure, pushing away the outer parts. The age and the composition of the star is relevant, too.
 
  • #3
SecretOfnumber said:
the biggest star in the universe is Canismajoris VY
Thanks
Let's not get ahead of ourselves. It's one of the largest stars by volume known in our galaxy.
This is not to say there are no larger ones, even within Milky Way. E.g., https://en.wikipedia.org/wiki/NML_Cygni. These stars are barely ~4-6kly away, at the edge of our ability to measure properties of individual stars. Compare to the diameter of the Galaxy: 100kly.
And let's not even mention the whole universe.

As for the VY CMa, it's only ~18 times as massive as the Sun and 180 times as massive as OGLE-TR-122b.
Therefore, you need 180 times as much of relatively cold gas(by mass) to make the larger one than you need for the smaller one.

Let's compare the volumes of gas clouds:

[tex]ρ\frac{4}{3}πR_1^3=m_1[/tex]
[tex]ρ\frac{4}{3}πR_2^3=m_2[/tex]
ρ is the density of the gas cloud


substituting
m1=180m2

[tex]R_1^3=180R_2^3[/tex]
[tex]R_1=180^\frac{1}{3}R_2[/tex]
[tex]R_1~=5.6R_2[/tex]

So you need just over five times larger(in radius) a gas cloud to produce CV CMa than OGLE-TR-122b.
 
  • #4
Thanks Bandersnatch,

You R right 1 of the Biggest "Known" star!

The other thing I would love to know is What causes the different size of stars? how "gravity" decide to make different sizes ?(I suppose gravity should become to the action after she made the star "GR gravity" wasn't the gas homogenous after cooling down of the universe?

Cheers
 
Last edited:
  • #5
The size of stars is determined by the availability of gases

As far as gases being homogeneous in the early universe one needs to consider that matter such as gases will quickly start to condense. So that even distribution will quickly change.
I should also point out that the term homogeneous is a term that in many descriptives or models is a term that can only be described at different size scales.

for example we describe our current universe as homogeneous, on a scale below 100Mpc we have galaxies,stars, large empty spaces etc.
So in this case we can only apply the homogeneous term on scales larger than 100 Mpc
 
  • #6
Let me elaborate on Mordred's comment.Perfect homogenity is unstable, in the same way as a needle standing on its sharp end is. It tends to be disrupted by the slightest of random motions and never reverts to the initial state.

Once a localised density spike appears in a uniform gas cloud, it gets exaggerated as it collapeses, and forms structures like groups of galaxies, galaxies themselves, stars and planets, depending on scale. Further collapse can be stopped by the conservation of angular momentum and (on small scales) internal kinetic energy of gas molecules(temperature) and radiation pressure.

Here's a nice simple program on Khan Academy that simulates a small, rotating cloud of particles collapsing under its own gravity:
http://www.khanacademy.org/cs/challenge-modeling-accretion-disks/1180451277
It might help in visualising the "lumping" of material.
You can change the variables, including the rotation and "star" formation rules.

Anyway. Gravity works well if the time scale is huge, or spatial scale is small(stars, planets etc.). So, once you end up with lumps of gas floating around a galaxy, they tend to stay roughly undisturbed. They're very diffuse, and often hot, so significant gravitational collapse might not happen for a very long time.

Usually there's some event that triggers the collapse, like an earlier star exploding and sending shockwaves through the medium to compress it enough. How much material ends up in any given star ends up pretty much random. (the program linked above illustrates this unpredictability)

So now you've got a number of stars with a range of masses. In the early stages of their lives(http://en.wikipedia.org/wiki/Main_sequence), it is only mass that determines their size. The larger the bigger(and brighter and hotter).
More massive stars' cores are compressed more highly than low-mass ones, so they produce more heat that pushes the outer parts outward. So the mass-radius relation is different from what you might expect from e.g., the constant density calculations in my post #3.
It looks something like this:
http://www.daviddarling.info/encyclopedia/M/mass-radius_relation.html
(it changes a bit depending on mass range)

The most massive stars theoretically possible have(iirc) ~250 solar masses(more massive would produce enough energy to blow away the extra mass). This one is close:
http://en.wikipedia.org/wiki/R136a1
And it's only ~35 times the radius of the sun.The really huge stars are all in their last phases of life, swelling to enormous proportions due the changing composition of their cores.
http://en.wikipedia.org/wiki/Stellar_evolution
Edit: the one factor I can think of that might influence the size of a star is the elemental composition of the collapsing molecular cloud.
Clouds with heavier elements will produce denser stars that will start fusion earlier. The resultant radiation flux will blow away the surrounding material that otherwise would accrete onto the star.
 
Last edited:

FAQ: Size of VY Canismajoris and gravity

What is the size of VY Canis Majoris?

The size of VY Canis Majoris is estimated to be between 1,800 and 2,100 times the size of our Sun.

How does VY Canis Majoris compare to other stars in terms of size?

VY Canis Majoris is one of the largest known stars and is significantly larger than our Sun. However, there are other stars that have been discovered to be even larger than VY Canis Majoris.

How does the size of VY Canis Majoris affect its gravity?

The size of VY Canis Majoris has a direct impact on its gravity. The larger a star is, the stronger its gravity will be. This is due to the star's mass increasing as its size increases.

Could VY Canis Majoris collapse into a black hole due to its size and gravity?

No, VY Canis Majoris is not massive enough to collapse into a black hole. It is estimated that a star needs to be at least 20 times more massive than our Sun to become a black hole.

How do scientists measure the size and gravity of VY Canis Majoris?

Scientists use a variety of techniques to measure the size and gravity of stars, including spectral analysis, parallax measurements, and mathematical models. In the case of VY Canis Majoris, its size has been estimated through observations of its luminosity and distance from Earth.

Similar threads

Back
Top