The balanced chemical equation for the reaction between SnO3 and H2 is SnO3(cr) + 2H2(g) → Sn(s) + 3H2O(g).
The reactants in this reaction are solid tin(IV) oxide (SnO3) and gaseous hydrogen (H2), while the products are solid tin (Sn) and gaseous water (H2O).
This is a redox (reduction-oxidation) reaction, as tin(IV) oxide (SnO3) is reduced to tin (Sn) and hydrogen (H2) is oxidized to water (H2O).
This reaction requires high temperatures and a reducing atmosphere, as well as a catalyst such as platinum or palladium to speed up the reaction.
This reaction is commonly used in the production of tin metal from tin(IV) oxide, as well as in the production of hydrogen gas. It is also used in the synthesis of various organic compounds, such as alcohols and aldehydes.