Solve Beer Mug Throwing Speed for 2m - Energy Conservation

In summary, the problem is to determine the initial speed at which a beer mug must be thrown in order to travel 2 meters on a table. The mass of the beer mug is 0.3 kg and the sliding loss factor between the table and beer mug is 0.3. The solution involves using the energy conservation principle and equating the work done by frictional force to the initial kinetic energy. After considering different factors, the correct initial speed is determined to be 3.43 m/s.
  • #1
domagoj412
9
0
Hello,
I have one problem...

In what initial speed must barmen throw beer mug on the table so it can travel 2 meters. Mass of the beer mug is 0,3 kg. Sliding loss factor between table and beer mug is 0,3.

I hope you have understand the question, because I am translating it from my mother language and some of terms are new to me...

I have to solve this problem using energy conservation principle.

So kinetic energy is wasted on (abrasion, attrition, friction, rub, Sliding loss - which is the right term):
Ek=W
W is F*s
F is m*g*u

It now becomes:

1/2*m*v^2=m*g*u

This can't be right... Mass is relevant here but with this equation it is equation abridged...
 
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  • #2
I'm not quite sure what exactly you mean by "sliding loss factor". If it is just the co-efficient of kinetic friction, then the result is independent of m. The initial speed would be 3.43 m/s.

If that is the case, then ma = -0.3*mg and v^2 = -2ax, giving the value of v.

If it means something else, please let us know.
 
  • #3
I looked up for the right term, yes I thought on Coefficient of friction which is 0,3.

But i need solve this with energy conversation...
 
  • #4
Equate work done by frictional force to initial KE.
 
  • #5
When you solve this

Kinetic energy = frictional force * x
Ek=F*x

You get 1,71 m/s

So which is correct?

1,71 or 3,43 m/s?
 
  • #6
Show your calculation.
 
  • #7
No, I made a mistake, it is 3,43.


Thank you.
 

FAQ: Solve Beer Mug Throwing Speed for 2m - Energy Conservation

What is the purpose of solving beer mug throwing speed for 2m?

The purpose of solving beer mug throwing speed for 2m is to better understand the physics and energy conservation principles involved in throwing a beer mug over a short distance. This can also help in improving accuracy and efficiency in beer mug throwing competitions.

How is energy conservation involved in solving beer mug throwing speed for 2m?

Energy conservation is involved in solving beer mug throwing speed for 2m because the kinetic energy of the beer mug before and after throwing should be equal in order to conserve energy. This can be calculated by considering factors such as the mass of the beer mug, the velocity at which it is thrown, and any external forces acting on it.

What factors affect the beer mug throwing speed for 2m?

The factors that affect the beer mug throwing speed for 2m include the mass and shape of the beer mug, the force applied while throwing, and any external factors such as air resistance. Additionally, the angle at which the beer mug is thrown can also affect its speed and trajectory.

How can the beer mug throwing speed for 2m be calculated?

The beer mug throwing speed for 2m can be calculated using the formula for kinetic energy: KE = 1/2mv^2, where m is the mass of the beer mug and v is its velocity. This calculation can be further adjusted to account for any external forces or factors that may affect the speed.

How can the results of solving beer mug throwing speed for 2m be applied?

The results of solving beer mug throwing speed for 2m can be applied in various ways. For example, it can be used to determine the optimal throwing technique and angle for achieving maximum speed and accuracy. This information can also be used to design better beer mugs that are more aerodynamic and easier to throw over short distances.

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