Solve for aa = 3.38 m/s^2Pulley Quesiton Homework: Tension in Massless String

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In summary, the conversation discusses an inclined ramp with two objects of different masses connected by a string and a pulley. An external force is exerted on the object on the ramp, resulting in both objects accelerating. The question asks for the tension in the string assuming frictionless surfaces and a massless string and pulley. The solution provided uses equations involving the external force, mass, and acceleration of the objects. The angle of the incline is also mentioned but not explicitly used in the solution.
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Homework Statement



The figure below shows an object on an inclined ramp of mass 0.98kg. The angle of the inclined surface is 32deg with the horizontal. The object on the ramp is connected to a second object of mass 2.13kg on a horizontal surface below an overhang that is formed by the inclined surface. Further, an external force of magnitude 9.00N is exerted on the object on the ramp. We observe both objects to accelerate. Assuming that the surfaces and the pulley are frictionless, and the connecting string and the pulley are massless, what is the tension in the string connecting the two objects?

[see picture attached]

Homework Equations


The Attempt at a Solution



FT+ 5.09N - 9N = 0.98a
Ft - 3.91 = 0.98a

-3.91 = -1.155a
 

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oneshot said:

Homework Statement



The figure below shows an object on an inclined ramp of mass 0.98kg. The angle of the inclined surface is 32deg with the horizontal. The object on the ramp is connected to a second object of mass 2.13kg on a horizontal surface below an overhang that is formed by the inclined surface. Further, an external force of magnitude 9.00N is exerted on the object on the ramp. We observe both objects to accelerate. Assuming that the surfaces and the pulley are frictionless, and the connecting string and the pulley are massless, what is the tension in the string connecting the two objects?

[see picture attached]

Homework Equations



The Attempt at a Solution



FT+ 5.09N - 9N = 0.98a
Ft - 3.91 = 0.98a

-3.91 = -1.155a
attachment.php?attachmentid=56994&d=1364015606.png


What's your question?

If you want your solution critiqued, you should show in more detail how you got those quantities.

Where does the angle of the incline come into play, etc. ?
 

FAQ: Solve for aa = 3.38 m/s^2Pulley Quesiton Homework: Tension in Massless String

1. What is a massless string?

A massless string is a theoretical concept used in physics problems to simplify calculations. It is assumed that the string has no mass and therefore does not contribute to the overall forces acting on the system.

2. How do you calculate tension in a massless string?

The tension in a massless string can be calculated by applying Newton's second law of motion. The tension in a massless string is equal to the force applied to one end of the string, since there is no mass to resist the force.

3. What is the significance of the acceleration, aa = 3.38 m/s^2, in this problem?

The acceleration, aa = 3.38 m/s^2, represents the acceleration of the mass attached to the pulley. It is a known value that is used to solve for the tension in the massless string.

4. How does the pulley affect the tension in the string?

The pulley does not affect the tension in the string because it is assumed to be massless. The tension in the string is solely determined by the forces acting on the pulley and the mass attached to it.

5. Can the tension in a massless string ever be greater than the applied force?

No, the tension in a massless string can never be greater than the applied force. This is because the massless string cannot resist the applied force and therefore the tension will always be equal to the applied force.

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