Solve Row-Echelon Form: 3x -y + 2z = -4

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In summary, the conversation discusses the use of row-echelon form to solve a system of equations, as opposed to elimination and substitution methods. The solutions for the given equations are x = -1, y = 5, and z = 2, but these values do not satisfy the equations. The use of Cramer's rule is also mentioned as a less efficient method for solving these equations.
  • #1
Bogrune
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Homework Statement


NOTE: This is not a homework question, rather it's a question I made up to practice using Row-Echelon. I know how to solve it easily using elimination or substitution, and by using Cramer's Rule (but my instructor suggests I rather not since it's too much work :P) The solutions are x = -1, y= 5, and z= 2

3x -y + 2z = -4
-4x +y -5z = -1
x +4y -z = 9

Can anyone give me an example of how to solve it using Row-Echelon Form?

Homework Equations





The Attempt at a Solution


I'm sorry! I'd try it myself, but I don't understand it at all, and I can't seem to study it without a textbook. Again, I know how to solve it easily by using Elimination and Substitution.
 
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  • #2
Well, first we'll need to put your system of equations into an augmented matrix, like so:

[tex]
\left[
\begin{array}{ccc|c}
3&-1&2&-4\\
-4&1&-5&-1\\
1&4&-1&9
\end{array}
\right]
[/tex]

Before we go any father, do you see where I got that?
 
  • #3
By setting up the x's on the first column, the y's on the second column, the z's on the third column, and the ='s (which is how my instructor names them) on the fourth column?
 
  • #4
Yep, pretty much. Now, you can work with this matrix until it is in row echelon form using certain rules, which I believe are as follows:

You can add any scalar multiple of a line to another line.
You can interchange two lines.
You can multiply any line by a nonzero scalar.

Now, first thing you'll want to do is get the top left entry to be 1, and then use that to zero both of the other left entries. What's the best way you can see to do that?
 
  • #5
By multiplying the first row by -4, and the second one by -3?
 
  • #6
Actually, if I were you, my first step would be to interchange rows 1 and 3, to get that 1 in the top left. Then you just need to add multiples of the first row to the second and third rows to zero out everything else in the left column.
 
  • #7
I'm sorry. I'll try analyzing it within a few hours, because I'm late for a meeting. I do apologize. :(
 
  • #8
Oh, no worries. It's past midnight for me here, so I'll probably go to bed anyway. Cheers!
 
  • #9
Bogrune said:

Homework Statement


NOTE: This is not a homework question, rather it's a question I made up to practice using Row-Echelon. I know how to solve it easily using elimination or substitution, and by using Cramer's Rule (but my instructor suggests I rather not since it's too much work :P) The solutions are x = -1, y= 5, and z= 2

3x -y + 2z = -4
-4x +y -5z = -1
x +4y -z = 9

Can anyone give me an example of how to solve it using Row-Echelon Form?

Homework Equations





The Attempt at a Solution


I'm sorry! I'd try it myself, but I don't understand it at all, and I can't seem to study it without a textbook. Again, I know how to solve it easily by using Elimination and Substitution.
When you are doing elimination or substitution, you are essentially getting the row-echelon form, although without explicitly using matrices: you are doing so-called Gaussian elimination.

Your instructor is right when he/she says not to use Cramer's rule. This is rarely used to solve real-world sized problems unless they have special structure that makes determinants easy to compute. It does, however, have its theoretical uses.

RGV
 
  • #10
You are going to get some really messy numbers because x = -1, y= 5, and z= 2 are not solutions to those equations. In particular (-1)+ 4(5)- (2)= 17, not 9,.
 

FAQ: Solve Row-Echelon Form: 3x -y + 2z = -4

How do you solve a system of equations using row-echelon form?

To solve a system of equations using row-echelon form, you need to first write the equations in a matrix form. Then, use elementary row operations to manipulate the matrix until it is in row-echelon form. Finally, solve for the variables by back-substituting starting from the bottom row.

What is the purpose of using row-echelon form in solving systems of equations?

Row-echelon form is used to simplify and organize a system of equations. It allows for easy identification of the leading variables and the dependent and independent variables. This form also makes it easier to solve for the variables using back-substitution.

Can you solve a system of equations using row-echelon form if there are more than three variables?

Yes, row-echelon form can be used to solve systems of equations with any number of variables. However, as the number of variables increases, the process of solving the system may become more complex and time-consuming.

Is there a specific order in which the elementary row operations should be applied?

Yes, there is a specific order in which the elementary row operations should be applied. The most common order is to first eliminate the lower rows and then the higher rows. This means performing row operations such as row swapping, row scaling, and row addition/subtraction on the bottom rows first before moving on to the higher rows.

Can you use row-echelon form to solve a system of equations with fractions or decimals?

Yes, row-echelon form can be used to solve a system of equations with fractions or decimals. It is important to keep track of the fractions or decimals and perform the row operations carefully to avoid any errors. It may also be helpful to convert the fractions or decimals to their equivalent form in terms of integers for easier calculation.

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