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TaurusSteve
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Ban my account please!Thanks!
TaurusSteve said:Ban my account please!Thanks!
Or you could just stop logging in...TaurusSteve said:Ban my account please!Thanks!
The solution to this equation is not a single point, but rather a set of points that satisfy both equations. In other words, the solution is a circle with a radius of 2, centered at the origin, in the xy-plane and a single point at z=-1 in the z-axis.
To graph these equations, you can plot the circle in the xy-plane with a radius of 2 and center at the origin. Then, plot a single point at z=-1 on the z-axis. This will represent the intersection of the circle and the z=-1 plane.
Yes, there are infinite solutions for this system of equations. Each point on the circle in the xy-plane and the single point at z=-1 in the z-axis is a valid solution.
Yes, you can also represent the solutions as ordered triples (x, y, z) where x and y are points on the circle in the xy-plane and z is the single point at z=-1 in the z-axis.
These equations are commonly used in geometry and physics to represent circles and points in 3-dimensional space. They can also be used to model various real-life scenarios, such as the motion of a pendulum or the path of a satellite orbiting the Earth.