Solving Centripetal Acceleration for Banked Turns

In summary: Anyway, the diagram would show the car, the road, and the wing in relation to each other. The x- and y-components of the normal force would be shown in the diagram. The x-component would be towards the car, and the y-component would be towards the wing. The force on the wing would be shown as a downward force, and the force on the road would be shown as an upward force.
  • #1
FortyFeet
1
0
Hey there. I took Physics B last year, but for some reason we never covered the banked turns when it comes to centripetal acceleration. So I need a bit of help on these two:

A curve with a 100 m radius on a level road is banked at the correct angle for a speed of 16 m/s. If an automobile rounds this curve at 30 m/s, what is the minimum coefficient of static friction needed between the tires and the road to prevent skidding?

and...

Aircraft experience a lift force (due to the air) that is perpendicular to the plane of the wings and to the direction of flight. A small airplane is flying at a constant speed of 250 km/h. At what angle from the horizontal must the wings of the airplane be tilted for the plane to execute a horizontal turn from east to north with a turning radius of 1900 m?

Thanks =D
 
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  • #2
Welcome to PF FortyFeet. We will help you but you must show some attempts at the problems first.

FortyFeet said:
A curve with a 100 m radius on a level road is banked at the correct angle for a speed of 16 m/s.
Thanks =D

Draw a little diagram with the two forces acting up on the car. "at the correct angle" means that the car will not tend to slip so it will not experience any frictional forces when going around the bend. This means only the normal force and weight are acting on the car.

Decompose the normal force into its x- and y-components.

Set the two force equations up in the x- and y-directions using Newton's second law. Post your two equations so that we can help you.
 
  • #3
andrevdh said:
Draw a little diagram

haha.. Sounds quite funny calling it 'little'. It's supposed to be a free-body diagram ah?
 

FAQ: Solving Centripetal Acceleration for Banked Turns

What is centripetal acceleration in a banked turn?

Centripetal acceleration is the inward acceleration experienced by an object moving in a circular motion. In a banked turn, this acceleration is directed towards the center of the turn, keeping the object on its curved path.

How is centripetal acceleration calculated in a banked turn?

The formula for calculating centripetal acceleration in a banked turn is a = v^2/r, where a is the acceleration, v is the velocity of the object, and r is the radius of the turn. This formula takes into account both the speed and the curvature of the turn.

What factors affect the necessary centripetal acceleration for a banked turn?

The necessary centripetal acceleration for a banked turn is affected by the speed of the object, the radius of the turn, and the angle of the bank. These factors determine the amount of force needed to keep the object on its curved path.

How does banking a turn affect the required centripetal acceleration?

Banking a turn can reduce the amount of required centripetal acceleration by allowing the force of gravity to assist in keeping the object on its curved path. This is achieved by tilting the surface of the turn at an angle, which helps to balance the forces acting on the object.

What is the relationship between centripetal acceleration and the angle of banking in a turn?

The angle of banking in a turn is directly related to the necessary centripetal acceleration. As the angle of banking increases, the necessary centripetal acceleration decreases. This is because a steeper bank allows for a greater component of the force of gravity to act as the centripetal force, reducing the amount of acceleration needed.

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