Solving Fifth Roots of z = 1 + √2

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In summary, the conversation discusses finding the five distinct fifth roots of a complex number, z=1+\sqrt{2}. The suggested method is to rewrite the number in the form z=(1+\sqrt{2}){\rm e}^{2\pi ni}, where n=0,1,2,... and then taking the fifth root. This results in 5 distinct roots in the form z^{1/5}=(1+\sqrt{2})^{1/5} \left \{ \cos \left ( \frac{2\pi n}{5} \right) +i \sin \left( \frac{2\pi n}{5} \right) \right \}. The conversation ends with gratitude
  • #1
dogma
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Here's a silly roots question that has my congested mind temporarily stumped:

Let [tex]z = 1 + \sqrt{2}[/tex]. Find the five distinct fifth roots of z.

Thanks in advance for helping me relieve the pressure.
 
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  • #2
Some of the roots are going to be complex, so the way I would tackle the problem is to rewrite your number in the form:

[tex]z=(1+\sqrt{2}){\rm e}^{2\pi ni}[/tex],

where n=0,1,2,... Then taking the fifth root gives:

[tex]z^{1/5}=(1+\sqrt{2})^{1/5} {\rm e}^{2\pi ni/5}[/tex],

which you can write in the form:

[tex]z^{1/5}=(1+\sqrt{2})^{1/5} \left \{ \cos \left ( \frac{2\pi n}{5} \right) +i \sin \left( \frac{2\pi n}{5} \right) \right \}[/tex].

Evaluating this for different n, should give 5 distinct roots.
 
  • #3
thank you very much for the insight...I now proceed to kick myself for not seeing it on my own {sound of kicking}

Thanks!
 

FAQ: Solving Fifth Roots of z = 1 + √2

What is the solution to the fifth root of z = 1 + √2?

The solution to the fifth root of z = 1 + √2 is a complex number that, when raised to the fifth power, equals 1 + √2.

How do you solve for the fifth root of z = 1 + √2?

To solve for the fifth root of z = 1 + √2, you can use the formula z^(1/5) = r(cos((θ + 2πk)/5) + i(sin((θ + 2πk)/5)), where r is the magnitude of z and θ is the argument of z. You can then plug in the values for r and θ to find the five possible solutions.

Can the fifth root of z = 1 + √2 be simplified?

Yes, the fifth root of z = 1 + √2 can be simplified to the form r(cos(θ/5) + i(sin(θ/5)), where r is the magnitude of z and θ is the argument of z.

Are there multiple solutions to the fifth root of z = 1 + √2?

Yes, there are five possible solutions to the fifth root of z = 1 + √2, since the fifth power of any complex number has five distinct values.

Can the fifth root of z = 1 + √2 be solved without using complex numbers?

No, the fifth root of z = 1 + √2 requires the use of complex numbers to find all possible solutions.

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