Solving for Tension & Acceleration of Forces in Diagram

In summary: He has drawn a FBD and found three equations for acceleration, but is unsure of how to proceed. You suggest equating the equations and using substitution to solve for A. Patrick has tried this, but is getting strange numbers and thinks it may be due to an algebra error. You suggest plugging in the values to the initial equations to check for mistakes.
  • #1
Tensaiga
43
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i drew a digram for the forces and i found out the equations for accerleration... then I'm stuck...

Question: Determine the tension in the strings, the acceleration, and how far the masses will go in 2.0s. (See attachement)

Well i drew a FBD, ,and i got three eqations for accerleration:
for mass 1 (100g):
A = (T2 - M1*G)/(M1)
A = (T2 - 0.1*9.8)/(0.1)

mass 2: (200g, on the floor)
A = (T1 - T2)/(M2)
A = (T1 - T2)/(0.2)

mass 3: (200g, going down on the right)
A = (M3*G - T1)/(M3)
A = (0.2*9.8 - T1)/(0.2)

Then what should i do after this? i can't equate 3 equations at once... can i?
 

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  • #2
Tensaiga said:
i drew a digram for the forces and i found out the equations for accerleration... then I'm stuck...

Question: Determine the tension in the strings, the acceleration, and how far the masses will go in 2.0s. (See attachement)

Well i drew a FBD, ,and i got three eqations for accerleration:
for mass 1 (100g):
(1) A = (T2 - M1*G)/(M1)
A = (T2 - 0.1*9.8)/(0.1)

mass 2: (200g, on the floor)
(2) A = (T1 - T2)/(M2)
A = (T1 - T2)/(0.2)

mass 3: (200g, going down on the right)
(3) A = (M3*G - T1)/(M3)
A = (0.2*9.8 - T1)/(0.2)

Then what should i do after this? i can't equate 3 equations at once... can i?
Why not? After all, if the string does not break the accelerations are all the same. Try inserting the expressions for T1 and T2 from equations 1 and 3 into 2. That will give you an equation with only one unknown: A.

AM
 
  • #3
yea i tried that, but a strange number came out... i will try again, maybe it's a algebra error.
 
  • #4
Tensaiga said:
yea i tried that, but a strange number came out... i will try again, maybe it's a algebra error.
Your equations look right. Did you solve for both tensions and for the acceleration? If so, there is an easu way to tell if you made an algebra mistake: just plug back your values in the initial equations! If it does not work, it shows that you made an algebra mistake.

Patrick
 

FAQ: Solving for Tension & Acceleration of Forces in Diagram

How do you calculate tension in a diagram?

Tension can be calculated by using Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In a diagram, tension can be represented by a force vector, and by using this equation, the tension can be solved for by rearranging the equation to solve for the unknown variable.

What is the relationship between tension and acceleration in a diagram?

In a diagram, tension and acceleration are directly related. This means that as the tension in a string or rope increases, the acceleration of the object connected to the string or rope will also increase. This relationship is due to Newton's second law of motion, which states that the net force acting on an object is directly proportional to its acceleration.

How do you draw a free body diagram to solve for tension and acceleration?

To draw a free body diagram for a problem involving tension and acceleration, you must first identify all the forces acting on the object in the problem. This includes the weight of the object, any external forces, and the tension in any strings or ropes. Next, draw a diagram with arrows representing the direction and magnitude of each force. Finally, use Newton's second law of motion to solve for the unknown variables, such as tension and acceleration.

Can you solve for tension and acceleration in a diagram without using Newton's laws?

No, it is not possible to solve for tension and acceleration in a diagram without using Newton's laws. These laws provide the fundamental principles for calculating forces and motion, and without them, it would be impossible to accurately determine the tension and acceleration in a diagram.

What are some real-world applications of solving for tension and acceleration in a diagram?

Solving for tension and acceleration in a diagram has many real-world applications, such as in engineering and construction, where understanding the forces acting on structures is crucial for their stability and safety. It is also used in physics experiments and simulations to predict the motion of objects and understand the underlying forces at play.

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