- #1
Piano man
- 75
- 0
Hi,
I'm reading up on Kepler's problem at the moment, and there's a step in the book that I don't understand.
Starting off with the equation of the path [tex]\phi=\int\frac{M dr/r^2}{\sqrt{2m[E-U(r)]-M^2/r^2}}+\mbox{constant}[/tex]
The step involves subbing in [tex]U=-\alpha/r[/tex], 'and effecting elementary integration' to get
[tex]\phi=\cos^{-1}\frac{(M/r)-(m\alpha/M)}{\sqrt{(2mE+\frac{m^2\alpha^2}{M^2}})}+\mbox{constant}[/tex]
But it doesn't look very elementary to me
Does anyone have any idea?
Thanks.
I'm reading up on Kepler's problem at the moment, and there's a step in the book that I don't understand.
Starting off with the equation of the path [tex]\phi=\int\frac{M dr/r^2}{\sqrt{2m[E-U(r)]-M^2/r^2}}+\mbox{constant}[/tex]
The step involves subbing in [tex]U=-\alpha/r[/tex], 'and effecting elementary integration' to get
[tex]\phi=\cos^{-1}\frac{(M/r)-(m\alpha/M)}{\sqrt{(2mE+\frac{m^2\alpha^2}{M^2}})}+\mbox{constant}[/tex]
But it doesn't look very elementary to me
Does anyone have any idea?
Thanks.