Solving Oscillation Problems with Steel Ruler Measurements

In summary, the steel ruler's tip oscillates with an amplitude of 1cm and a frequency of 5Hz. In order to determine the path the tip travels within 2 seconds, we need to calculate the period of oscillations. This can be done using the equation T=2pi sqrt(L/g) if we know the radius of the pendulum, but in this case, the ruler is acting like a mass-spring system and it's tip traces a straight line instead of an arc. Therefore, we can determine the distance traveled by the tip in one complete oscillation, which is 4cm. Since the period is 1/5 seconds, there are 10 oscillations in 2 seconds and the tip travels a
  • #1
Noiro
24
0

Homework Statement




Steel ruler tip's oscillation amplitude is 1cm, frequency 5Hz. What is the path the ruler's tip goes within 2 seconds?

Homework Equations



I think I need to find a period so the equations would be T=1/5 s but I'm not sure.

The Attempt at a Solution



I don't know how to solve it so I would be grateful if someone could help me.
 
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  • #2
Noiro said:

Homework Statement




Steel ruler tip's oscillation amplitude is 1cm, frequency 5Hz. What is the path the ruler's tip goes within 2 seconds?

Homework Equations



I think I need to find a period so the equations would be T=1/5 s but I'm not sure.

The Attempt at a Solution



I don't know how to solve it so I would be grateful if someone could help me.
What does the question mean by "path"? Does it mean the arc length, or the normal deviation, or the tangential deviation?
 
  • #3
Hootenanny said:
What does the question mean by "path"? Does it mean the arc length, or the normal deviation, or the tangential deviation?

It is the arc length
 
  • #4
Noiro said:
It is the arc length
Oke doke.

As you correctly say, the period of oscillations is 1/5 seconds. What else do you think we need to work out in order to solve this problem?
 
  • #5
Hootenanny said:
Oke doke.

As you correctly say, the period of oscillations is 1/5 seconds. What else do you think we need to work out in order to solve this problem?

Maybe a phase of an oscillation? I'm not sure though. What do we need?
 
  • #6
Noiro said:
Maybe a phase of an oscillation? I'm not sure though. What do we need?
What do you usually need to work out the arc length (two things)?
 
  • #7
Hootenanny said:
What do you usually need to work out the arc length (two things)?

Measure of a central angle and radius?
 
  • #8
Noiro said:
Measure of a central angle and radius?

Scratch what I said for now.
Not to interlope, but the arc length is given, and you can't calculate it using the central angle and radius as those are unknowns for this problem.

I think what Hootenanny was trying to steer you towards was the distance traveled per period, try finding that and then try and see what distance the tip travels in 2 seconds.
 
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  • #9
Noiro said:
Measure of a central angle and radius?
Correct. So, what is the radius?
 
  • #10
RoyalCat said:
but the arc length is given
No it isn't, the amplitude is given, but that isn't the arc length.
RoyalCat said:
and you can't calculate it using the central angle and radius as those are unknowns for this problem.
Erm... yes you can.
 
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  • #11
Hootenanny said:
Correct. So, what is the radius?

I don't know. What is it?
 
  • #12
Noiro said:
I don't know. What is it?
You have to work it out...

HINT: If you weren't given the frequency, but were instead given the radius of the pendulum, what equation would you use to determine the period of the oscillations?
 
  • #13
Hootenanny said:
You have to work it out...

HINT: If you weren't given the frequency, but were instead given the radius of the pendulum, what equation would you use to determine the period of the oscillations?

I think it's T=2pi sqrt(L/g)
 
  • #14
Noiro said:
I think it's T=2pi sqrt(L/g)
That is correct.

Just one minor point, do you have a diagram associated with this question? I'm assuming that this steel rule is hanging vertically and is oscillating in plane like a pendulum. Would that be correct?
 
  • #15
Hootenanny said:
That is correct.

Just one minor point, do you have a diagram associated with this question? I'm assuming that this steel rule is hanging vertically and is oscillating in plane like a pendulum. Would that be correct?

No it's embedded in a clamp. I hope you can imagine what it looks like.
 
  • #16
C'mon, get on MS Paint and draw a diagram. A lot of us here are lazy. :shy:
 
  • #17
Noiro said:
No it's embedded in a clamp. I hope you can imagine what it looks like.
Ahh I see. I had originally envisaged a pendulum-like set up. However, this case actually turns out to be a lot simpler than the case that I had originally envisaged. The steel rule is acting like a mass-spring system and in this case to a fairly high degree of accuracy the tip of the rule doesn't trace an arc. Instead, it traces [approximately] a straight line.

So, let's forget about determining the radius. Instead, can you tell me how far the tip of the rule travels in one complete oscillation?
 
  • #18
Hootenanny said:
Ahh I see. I had originally envisaged a pendulum-like set up. However, this case actually turns out to be a lot simpler than the case that I had originally envisaged. The steel rule is acting like a mass-spring system and in this case to a fairly high degree of accuracy the tip of the rule doesn't trace an arc. Instead, it traces [approximately] a straight line.

So, let's forget about determining the radius. Instead, can you tell me how far the tip of the rule travels in one complete oscillation?

Well if amplitude is 1cm then I guess it's 2cm. Am I right?
 
  • #19
Amplitude is the maximal displacement from the point of equilibrium.
The period is the length of time it takes the particle to return to its initial position, the length of how many amplitudes would a particle have to cover in distance over the course of 1 period?

Another hint:
This little diagram should hopefully make the point a bit more clear:
|---eq---|
--- is the amplitude, not --- ---.
 
  • #20
Noiro said:
Well if amplitude is 1cm then I guess it's 2cm. Am I right?
As RoyalCat has said, 1cm is the maximal displacement (i.e. the distance between its equilibrium position and one of the turning points). What is a full oscillation in terms of turning points and the equilibrium position?
 
  • #21
Hootenanny said:
As RoyalCat has said, 1cm is the maximal displacement (i.e. the distance between its equilibrium position and one of the turning points). What is a full oscillation in terms of turning points and the equilibrium position?

So it's 4cm right?
 
  • #22
Noiro said:
So it's 4cm right?
Correct. So, if the ruler has a period of 1/5 seconds, how many oscillations occur in 2 seconds? Hence how far does the tip of the ruler travel in 2 seconds?
 
  • #23
Hootenanny said:
Correct. So, if the ruler has a period of 1/5 seconds, how many oscillations occur in 2 seconds? Hence how far does the tip of the ruler travel in 2 seconds?

So in 2 seconds occur 10 oscillations and tip of the ruler travels 40cm. Am I right?
 
  • #24
Noiro said:
So in 2 seconds occur 10 oscillations and tip of the ruler travels 40cm. Am I right?
Sounds good to me!

Apologies for the earlier confusion regarding the orientation of the ruler. Thanks to RoyalCat for pointing out the correct set up.
 
  • #25
Hootenanny said:
Sounds good to me!

Apologies for the earlier confusion regarding the orientation of the ruler. Thanks to RoyalCat for pointing out the correct set up.

No problem. Thanks Hootenanny and RoyalCat you really helped me!
 

FAQ: Solving Oscillation Problems with Steel Ruler Measurements

What is the purpose of solving oscillation problems with steel ruler measurements?

The purpose of solving oscillation problems with steel ruler measurements is to accurately measure and analyze the oscillations of objects, such as pendulums or springs, in order to understand their motion and behavior.

How do steel ruler measurements help in solving oscillation problems?

Steel ruler measurements provide a precise and reliable way to measure the amplitude, frequency, and period of oscillations. This data can then be used to calculate important parameters, such as the object's mass or spring constant.

What are some common techniques for solving oscillation problems with steel ruler measurements?

Some common techniques include measuring the time for a certain number of oscillations, measuring the distance the object travels in one oscillation, and using trigonometric functions to analyze the data.

Are there any potential errors or limitations in using steel ruler measurements for solving oscillation problems?

Yes, there are some potential errors and limitations. For example, the ruler may not be perfectly straight, there could be human error in recording the measurements, and external factors such as air resistance may affect the motion of the object.

How can solving oscillation problems with steel ruler measurements be applied in real-world scenarios?

Solving oscillation problems with steel ruler measurements can be applied in various fields such as engineering, physics, and even music. For example, it can help in designing stable structures, understanding the behavior of mechanical systems, and tuning musical instruments.

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