- #1
Tom McCurdy
- 1,020
- 1
I am very tired and am not sure if i am doing this right
[tex] convert into P=Poe^(^k^t^) [/tex]
I came up with
[tex] P=15e^(^l^n^(^1^.^5^)^t^) [/tex]
from
[tex] P=15(1.5)^t[/tex]
haha
nvm i think i got it while I was trying to figure out latex
wow--- the answer was so easy it seemed wrong
[tex] convert into P=Poe^(^k^t^) [/tex]
I came up with
[tex] P=15e^(^l^n^(^1^.^5^)^t^) [/tex]
from
[tex] P=15(1.5)^t[/tex]
haha
nvm i think i got it while I was trying to figure out latex
wow--- the answer was so easy it seemed wrong