- #1
Titans86
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Can I use this logic?
I'm wondering if I can use this kind of logic to solve:
[tex]\sum\frac{(n+1)^n}{n^{(n+1)}}[/tex] Converges or diverges
[tex] \frac{(n+1)^n}{n^{(n+1)}} \geq \frac{(n)^n}{n^{(n+1)}} [/tex]
And
[tex] \frac{(n)^n}{n^{(n+1)}} = n [/tex] , which diverges
Therefor:
[tex]\sum\frac{(n+1)^n}{n^{(n+1)}}[/tex] Diverges
Homework Statement
I'm wondering if I can use this kind of logic to solve:
[tex]\sum\frac{(n+1)^n}{n^{(n+1)}}[/tex] Converges or diverges
The Attempt at a Solution
[tex] \frac{(n+1)^n}{n^{(n+1)}} \geq \frac{(n)^n}{n^{(n+1)}} [/tex]
And
[tex] \frac{(n)^n}{n^{(n+1)}} = n [/tex] , which diverges
Therefor:
[tex]\sum\frac{(n+1)^n}{n^{(n+1)}}[/tex] Diverges
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