- #1
A_I_
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g(x) is a function of x that we do not know its form.
y(t) =(1/2) integral 0-->t [ sin(2t-2x)*g(x) ]dx
i tried to use integration by substitution and by parts
but the problem is that g(x) has an unknown form.
the actual problem is that
y" +cy' +dy = g(t) y(0) = y0 y'(0) = y'0
we are asked to find c,d,y0,y'0
knowing that y(t) is the solution of the second order differential equation.
i would appreciate your help.
Thanks,
Joe
y(t) =(1/2) integral 0-->t [ sin(2t-2x)*g(x) ]dx
i tried to use integration by substitution and by parts
but the problem is that g(x) has an unknown form.
the actual problem is that
y" +cy' +dy = g(t) y(0) = y0 y'(0) = y'0
we are asked to find c,d,y0,y'0
knowing that y(t) is the solution of the second order differential equation.
i would appreciate your help.
Thanks,
Joe