Thevenin equivalanet and max power question

In summary, the conversation discusses a problem involving circuit analysis and the use of a website to share and discuss the solution. The problem involves calculating voltage and current in a circuit, using a voltage-controlled voltage source, and understanding mutual inductance. It also includes a tip for posting problems directly in the forum for better response rates.
  • #1
takeiteasy
4
0
could you check this question if i am doing it right?

http://vyew.com/844710/circuit_analysis_examples
 
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  • #2
takeiteasy said:
could you check this question if i am doing it right?

http://vyew.com/844710/circuit_analysis_examples

Welcome to PF,

That website is pretty neat, although it would have been much better (for us and for your response rate) to post the problem and your steps directly here, in the forum.

Your first part is correct (it's just a voltage divider). The current through the loop on the left is I = (8 V)/(4 kΩ) = 2 mA. Then the voltage v0 across the 1k resistor is I*R = (2 mA)*(1 kΩ) = 2 V.

Your next step is wrong. The diamond-shaped thing is a voltage-controlled voltage source. Hence it is providing 240 V (NOT 240 A).

It's really unclear what the problem is asking for, but if you are trying to solve for the voltage between terminals 'a' and 'b', then just use the same technique for the right loop as for the left loop. Find the current through the loop using the given voltage and the total resistance. Then use this current to find the voltage across the 40k resistor. Be careful with signs/directions.

EDIT: I see that you have essentially done the second part correctly as well, in spite of the mistake with the units.
 
  • #3
thank you,cepheid=) i just can't believe how i treat the voltage as current. brain explosion=)


Can you look at this mutual inductance problem and explain the sign and dot logic behind it please?

http://vyew.com/room#/844710/circuit_analysis_examples
 

FAQ: Thevenin equivalanet and max power question

What is Thevenin equivalent?

The Thevenin equivalent is a simplified circuit representation of a complex circuit, consisting of a single voltage source in series with a single resistor. This equivalent circuit behaves the same as the original circuit at the terminals where it is connected.

How is Thevenin equivalent calculated?

The Thevenin equivalent is calculated by finding the open-circuit voltage at the terminals of the circuit and the equivalent resistance between those terminals. The open-circuit voltage is the voltage measured when no current flows through the circuit, and the equivalent resistance is the resistance that would produce the same current as the original circuit.

3. What is the purpose of finding Thevenin equivalent?

The purpose of finding Thevenin equivalent is to simplify a complex circuit into a more manageable and easier to analyze circuit. This is especially useful when dealing with large networks of interconnected circuits or when trying to determine the behavior of a particular component in a larger circuit.

4. What is the maximum power transfer theorem?

The maximum power transfer theorem states that the maximum amount of power will be transferred from a source to a load when the load resistance is equal to the Thevenin resistance of the source. In other words, the load will receive the maximum amount of power when it is matched to the source.

5. How do you find the maximum power in a circuit?

To find the maximum power in a circuit, you can use the maximum power transfer theorem and calculate the Thevenin resistance of the source. Then, you can use this value to determine the load resistance that will result in maximum power transfer. Once the load resistance is known, the maximum power can be calculated using the formula P = V^2/R, where V is the open-circuit voltage and R is the load resistance.

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