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mmoadi
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Homework Statement
Two blocks (m1 = 0.02 kg, m2 = 0.03 kg, v1 = 1.5 m/s, v2 = 0.5 m/s) are sliding without friction on a surface. They are approaching each other at angle θ = 60º. In what direction and with how much velocity do we have to push the third block (m3 = 0.05 kg) against the first two blocks, so that when they crash they will come to rest?
Homework Equations
p=mv
The Attempt at a Solution
First two blocks:
G(x)= m(2)v(2)*(-sin θ)
G(y)= m(1)v(1) + m(2)*cos θ
Third block:
G(3x)= sin θ
G(3y)= m(1)v(1) – m(2)v(2)*cos θ
For the direction of the third block:
tan θ’= m(2)v(2)*sin θ / m(10v(1) + m(2)v(2)*cos θ → θ’= 19.1º
For the velocity of the third block:
G(3)= m(3)v(3) → v(3)= G3 / m(3)
G3= sqrt(m(1)²v(1)² + m(2)²v(2)² +2m(1)v(1)m(2)v(2)*cos θ)= 0.039686
v(3)= G3 / m(3)= 0.79372 m/s
Are my calculations correct?
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