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chawki
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Homework Statement
Three identical blocks, each of mass 0.6 kg, are connected by light strings. Assume that they lie on a frictionless, horizontal surface and are observed to have an acceleration of 4.0 m/s2 under the action of a force F.
Homework Equations
Calculate F and two tension forces Tbc and Tab
The Attempt at a Solution
by applying Newton second law on each block and then by projection on xx axis, we get:
On A:
F-Tab=m*a----(1)
On B:
Tab-Tbc=m*a----(2)
On C:
Tbc=m*a----(3)
(1)+(2)+(3) [tex]\RightarrowF=3*m*a[/tex]
F=7.2N
And then from (3) we have Tbc=m*a=0.6*4
Tbc=2.4N
From (1) we get -Tab=(m*a)-F
-Tab= (0.6*4)-7.2
Tab=4.8N
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