Torque / Static Equilibrium Question

In summary, the conversation discusses a question about a ladder leaning against a frictionless wall and the minimum angle at which it will not slip. The conversation includes equations and variables used to solve the problem, and the individual eventually finds their mistake and obtains the correct answer.
  • #1
ohlhauc1
27
0
I need help with the following question.

1. A uniform ladder of mass M and length L leans at an angle A against a frictionless wall. If the coefficient of static friction between the ladder and the ground is Q, what is the minimum angle at which the ladder will not slip?

Answer so far:
let T stand for torque

Tladder + TNwall = 0
rFcosA + rFsinA = 0
LFcosA = -LFsinA
mgcosA / sinA = Ffriction
mg = FfrictiontanA
(1 / QcosA) = tanA
A = tan^-1(1 / QcosA)

*The real answer is supposed to be A = tan^-1(1 / 2Q)

I was wondering if you could tell me what I did wrong, and what I should do to get the right answer. Thanks!
 
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  • #2
Can cosA equal Q, which is actually mu?
 
  • #3
ohlhauc1 said:
I need help with the following question.

1. A uniform ladder of mass M and length L leans at an angle A against a frictionless wall. If the coefficient of static friction between the ladder and the ground is Q, what is the minimum angle at which the ladder will not slip?

Answer so far:
let T stand for torque

Tladder + TNwall = 0
rFcosA + rFsinA = 0
LFcosA = -LFsinA
mgcosA / sinA = Ffriction
mg = FfrictiontanA
(1 / QcosA) = tanA
A = tan^-1(1 / QcosA)

*The real answer is supposed to be A = tan^-1(1 / 2Q)

I was wondering if you could tell me what I did wrong, and what I should do to get the right answer. Thanks!
Maybe its just the notation I can't follow, but I'm not seeing some things I think I should see. What is the normal force of the floor on the ladder? What is the friction force in terms of the normal force? What is the normal force of the wall on the ladder. Is that your r? I can't see you having a net zero torque equation with less than three torques.

Please define your variables.
 
  • #4
I put my pivot point at the base of the ladder so the normal force of the floor on the ladder would be 0. The friction force would be equal in magnitude to the normal force the wall exerts on the top of the ladder. r is the length of the ladder (L) because it represents the length of the lever arm a.k.a. ladder.

T represents torque
Q represents mu, the coefficient of friction
A represents theta, the angle
M represents the mass of the ladder
F represents force

Does this help?
 
  • #5
Got It!

I was able to get the answer, so you do not have to reply. I found my mistake! :)
 

FAQ: Torque / Static Equilibrium Question

What is torque?

Torque is a measure of the rotational force that is applied to an object. It is calculated by multiplying the force applied by the distance from the pivot point or axis of rotation.

How is torque different from force?

While force is a measure of the linear or straight-line push or pull on an object, torque is a measure of the rotational force on an object. Force is typically measured in Newtons (N), while torque is measured in Newton-meters (Nm).

What is static equilibrium?

Static equilibrium refers to a state in which an object is not moving and has no net forces acting on it. In other words, the forces acting on the object are balanced, resulting in a state of rest or constant motion.

How is torque related to static equilibrium?

In order for an object to be in static equilibrium, the sum of all the torques acting on the object must be equal to zero. This means that the rotational forces are balanced and the object will remain in a state of rest or constant motion.

What factors affect the torque on an object?

The magnitude of the force applied, the distance from the pivot point, and the angle at which the force is applied are all factors that affect the torque on an object. The longer the distance from the pivot point, the greater the torque, and the more perpendicular the force is to the object, the greater the torque will be.

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