Translating motion graphs. Dt to vt

In summary, when translating a position time graph to a velocity time graph, you do not use a step function if a curve line is followed by a straight diagonal line. The curved section represents accelerated motion, which is translated into a diagonal line in the velocity time graph. The diagonal line in the position time graph signifies constant velocity, which is represented by a horizontal line in the velocity time graph. Only in cases where there are two motions with different constant speeds would a step function be used in the velocity time graph.
  • #1
kencamarador
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I am so confuse! It's regarding translating motion graphs.

When translating a position time graph to a velocity time graph, if a curve line is followed by a straight diagonal line (both going up) do I use a step function?

Cause in this video http://m.youtube.com/#/watch?v=EZXLkAYjmR0&desktop_uri=/watch?v=EZXLkAYjmR0

At 3:04. He drew a diagnal line without calculating the slope... Isn't he suppose to use a step function?
 
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  • #2
kencamarador said:
I am so confuse! It's regarding translating motion graphs.

When translating a position time graph to a velocity time graph, if a curve line is followed by a straight diagonal line (both going up) do I use a step function?

Cause in this video http://m.youtube.com/#/watch?v=EZXLkAYjmR0&desktop_uri=/watch?v=EZXLkAYjmR0

At 3:04. He drew a diagnal line without calculating the slope... Isn't he suppose to use a step function?

The two sloping sections before and after the curved line can be used to find the constant velocities before and after the acceleration section. The presenter has possibly assumed [for simlicity] that the acceleration between those two sections was constant. Does the curved section look like it may be parabolic? [I can't play the video].
 
  • #3
kencamarador said:
He drew a diagnal line without calculating the slope... Isn't he suppose to use a step function?

No, he souldn't use a step function in such a case.
Curve line in d-t representation means accelerated motion (suppose the curve line is a parabola for simplicity, i.e. uniform acceleration)... then in the v-t representation it is a diagonal line, meaning that velocity is changing at constant rate.

Then the diagonal line in d-t representation means constant velocity. In v-t representation this is instead a straight horizontal line.

Therefore what you get is a diagonal line joined to an horizontal line. You would have a step function in v-t representation only in case you have two motions both at constant speed but with different speed (and at some point speed has to change instantaneously but you do not know why, it is not a realistic situation of course); in this case the d-t representation would be just two diagonal lines with different slopes.
 

FAQ: Translating motion graphs. Dt to vt

What is the difference between a distance-time graph and a velocity-time graph?

A distance-time graph shows the distance an object travels over a period of time, while a velocity-time graph shows the object's velocity (speed and direction) over time. Distance-time graphs have distance on the y-axis and time on the x-axis, while velocity-time graphs have velocity on the y-axis and time on the x-axis.

How do you calculate velocity from a distance-time graph?

Velocity can be calculated by finding the slope of the line on a distance-time graph. The slope is equal to the change in distance divided by the change in time. This will give you the average velocity over that time interval.

Can you determine the acceleration of an object from a velocity-time graph?

Yes, acceleration can be determined from a velocity-time graph by finding the slope of the line. The slope is equal to the change in velocity divided by the change in time. The steeper the slope, the greater the acceleration.

How can you tell if an object is moving at a constant speed from a distance-time graph?

If the distance-time graph is a straight line with a constant slope, then the object is moving at a constant speed. This means that the object is covering the same distance in the same amount of time, resulting in a constant velocity.

What does the area under a velocity-time graph represent?

The area under a velocity-time graph represents the displacement (change in position) of an object. This means that the total area under the graph is equal to the total distance traveled by the object.

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