- #1
nhmllr
- 185
- 1
Homework Statement
This is only a step in a bigger example problem on trig substitution
2/3 *x2 = sin2[tex]\theta[/tex]
[tex]\sqrt{}2/3[/tex] * x =sin[tex]\theta[/tex]
[tex]\theta[/tex] = arcsin([tex]\sqrt{}2/3[/tex] * x)
and
x = [tex]\sqrt{}3/2[/tex] * sin[tex]\theta[/tex]
This makes sense
Then I saw
dx / d[tex]\theta[/tex] = [tex]\sqrt{}3/2[/tex] * cos[tex]\theta[/tex]
Uh... why?
Homework Equations
Regular trig equations
The Attempt at a Solution
I have no idea