- #1
Phyzwizz
- 60
- 0
This is a problem from a quiz I had awhile ago, I got the answer correct, but I'm reviewing for a test and I completely forget how I did it. Can someone please show me what I did?
sec4x=2
secx=2
x=π/3 + 2nπ ---> x=π/12+2nπ/4
x=5π/3 + 2nπ ---> x=5π/12+2nπ/4
π=pi
p.s. I mostly just forget how to get the value for sec x= 2 how did I get π/3 and 5π/3
Thanks!
sec4x=2
secx=2
x=π/3 + 2nπ ---> x=π/12+2nπ/4
x=5π/3 + 2nπ ---> x=5π/12+2nπ/4
π=pi
p.s. I mostly just forget how to get the value for sec x= 2 how did I get π/3 and 5π/3
Thanks!