- #1
RadicalAlchmy
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A 6.0kg box is on a frictionless 35° slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.0kg weight. What is the tension in the string if the 6.0kg box is held in place, so that it cannot move?
m1= 6.0kg
m2= 2.0kg
θ=35°
So, for Box 1 to be held in place so that it doesn't move, the net force has to be equal to zero. If we tilt our coordinate system 35°,
Fnet,x = T + Gx
0 = T - mgsinθ
T = mgsinθ
T = (6.0kg)(9.8m/s2)sin(35°)
T = 33.726269N
That's the only way that I can think to do this question. The online assignment is telling me that I'm flat wrong. Is there something that I'm missing?
m1= 6.0kg
m2= 2.0kg
θ=35°
So, for Box 1 to be held in place so that it doesn't move, the net force has to be equal to zero. If we tilt our coordinate system 35°,
Fnet,x = T + Gx
0 = T - mgsinθ
T = mgsinθ
T = (6.0kg)(9.8m/s2)sin(35°)
T = 33.726269N
That's the only way that I can think to do this question. The online assignment is telling me that I'm flat wrong. Is there something that I'm missing?