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Homework Statement
consider a capacitor with circular plates of radius a, separated by a distance d (d<<a) and [itex]V(t)=V_{0}sin(wt)[/itex]
a)Considering the z axis to be the capacitor axis, verify that the electric field between the plates is , in good approximation, given by [itex]\vec{E}(t)\approx E_{0} sin(wt)\hat{e}_{z}[/itex].
What is the expression of [itex]E_{0}[/itex] ?
In which conditions is adequate this approximation of [itex]\vec{E}(t)[/itex] ?
Homework Equations
[itex] \vec{E}= \nabla V = \hat{e}_{r} \frac{\partial V}{\partial r} + \hat{e}_{\varphi} \frac{\partial V}{\partial \varphi} + \hat{e}_{z} \frac{\partial V}{\partial z} [/itex]
[itex]q=C V[/itex]
The Attempt at a Solution
I tried to find the electric field trough the above gradient formula but V has no dependence on r, phi, or z.
I also tried trough the second equation and got [itex]\vec{E}(t)= -\frac{q_{0}}{ \epsilon_{0} A} sin(wt) \hat{e}_{z}[/itex] with [itex]E_{0}= -\frac{q_{0}}{ \epsilon_{0} A} [/itex] but then I can't explain why is it just an approximation and in which conditions is it a good aproximation
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