- #1
Sabres151
- 14
- 0
Here's the question:
It is determined by immersing a crown in water that its volume is 26in^3 = 0.015ft^3.
What would its weight be if it were made of pure gold?
What would its weight be if it half of its volume were gold and half lead?
I'm not sure how to solve. I know this for gold:
D = 19,300kg/m^3
Dw = 1200lb/ft^3
I thougt the two equations needed would be the following:
m = V X D (since we know volume)
followed by...
W = mg, where m is solved for above and g = 9.8... My answer of 2837 didn't make much sense...
It is determined by immersing a crown in water that its volume is 26in^3 = 0.015ft^3.
What would its weight be if it were made of pure gold?
What would its weight be if it half of its volume were gold and half lead?
I'm not sure how to solve. I know this for gold:
D = 19,300kg/m^3
Dw = 1200lb/ft^3
I thougt the two equations needed would be the following:
m = V X D (since we know volume)
followed by...
W = mg, where m is solved for above and g = 9.8... My answer of 2837 didn't make much sense...