What Does Self-Adjointness in Linear Operators Mean?

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In summary, self-adjointness is a property of linear operators where the operator is equal to its own adjoint, making it symmetric with respect to the inner product on the vector space.
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yifli
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It is known that T in Hom(V) is self-adjoint if (Ta,b)=(a,Tb)

Let \theta be the isomorphism from V to V*, then (Ta, b)=(a,Tb) can be written as

[tex]\theta_b(Ta)=\theta_{Tb}(a)\rightarrow (T^*(\theta_b))(a)=\theta_{Tb}(a)\rightarrow T^*\circ \theta = \theta \circ T \rightarrow \theta^{-1} \circ T^* \circ \theta=T[/tex]
where T* is the adjoint of T

So T is self-adjont means through certain transformation, T* can be transformed to T itself.

Is my interpretation of self-adjointness correct?
 
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Your interpretation of self-adjointness is correct. The concept of self-adjointness is a fundamental property of linear operators in a vector space. It means that an operator is equal to its own adjoint, or in other words, it is symmetric with respect to the inner product defined on the vector space. This property is important because it allows for the simplification of many mathematical calculations and also has important physical implications in quantum mechanics and other areas of physics. Your explanation using the isomorphism \theta is a clear and concise way of understanding this property.
 

FAQ: What Does Self-Adjointness in Linear Operators Mean?

What is the definition of self-adjointness?

Self-adjointness is a property of a linear operator or matrix where the operator is equal to its own adjoint. In other words, the operator and its adjoint are the same when written in terms of their corresponding inner products.

How is self-adjointness related to symmetry?

If a linear operator is self-adjoint, it means that it has a symmetric matrix representation. This means that the operator is symmetric with respect to its diagonal elements, and the order of the matrix does not change when taking its transpose.

What is the significance of self-adjointness in quantum mechanics?

In quantum mechanics, self-adjoint operators represent physical observables, such as energy, momentum, and angular momentum. The fact that these operators are self-adjoint guarantees that their corresponding eigenvalues are real, which is crucial for the interpretation of physical measurements.

Can a non-self-adjoint operator be made self-adjoint?

Yes, a non-self-adjoint operator can be made self-adjoint through a process called self-adjoint extension. This involves extending the domain of the operator to include additional functions that satisfy certain conditions, resulting in a self-adjoint operator.

How is self-adjointness related to the spectral theorem?

The spectral theorem states that every self-adjoint operator has a complete set of orthogonal eigenvectors with real eigenvalues. This allows for the diagonalization of the operator, making it easier to solve equations involving the operator and interpret the results in terms of physical observables.

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