- #1
ee1215
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Homework Statement
These two waves travel along the same string:
y1(x,t)=7.00mm*sin(2pi x - 428pi t +0.38pi)
y2(x,t)=6.00mm*sin(2pi x - 428pi t + 0.93pi)
A) amplitude in mm
B) phase angle(relative to wave 1) of resultant wave
C) if third wave of amplitude 7.40mm is also to be sent along the string in same direction as first two, what should be its phase angle in order to maximize the amplitude of the new resultant wave?
Homework Equations
Amplitude would then be sqrt[(veritcal)^2+(horizontal)^2]
Phase angle = tan^-1 (vert/horiz)
The Attempt at a Solution
Need to find horizontal and vertical:
7.00cos(0.38pi)+6.00cos(0.93pi) - horizontal
7.00sin(0.38pi)+6.00sin(0.93pi) - vertical
For horizontal I got 12.98mm and verical 0.452mm but when using the equations I get the incorrect answer so I am doing something wrong with calculating horizontal and vertical.