- #1
B-80
- 73
- 1
An elevator and its load have a combined mass of 1500 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 11 m/s, is brought to rest with constant acceleration in a distance of 43 m.
First I found the time it to to decelerate
D=(V+Vo)/2 T
gave me a value of .78seconds
plugged it into V=Vo+at
a=14.1m/s^2
F=ma
so the force is 1500Kg * (9.8+14.1) which is 35850
thats wrong, thanks in advance
First I found the time it to to decelerate
D=(V+Vo)/2 T
gave me a value of .78seconds
plugged it into V=Vo+at
a=14.1m/s^2
F=ma
so the force is 1500Kg * (9.8+14.1) which is 35850
thats wrong, thanks in advance