- #1
The answer should be M/H x 2A.Suyash Singh said:Homework Statement
Part d of attached question
Homework Equations
Solenoid equations
B=uo n i
The Attempt at a Solution
B (absence)=B (presence)
Uo n (i+im)=u n i
im=798A
But answer is 794A.[/B]
I just did, in post 3.Suyash Singh said:Can you guys give a formula for magnetising current for solenoid? Every book gives for transformer but not for solenoid
A solenoid is a coil of wire that is wound in a helical shape. It is commonly used in electromagnets and other electrical devices.
When an electric current flows through a solenoid, it creates a magnetic field. The strength of the magnetic field can be controlled by changing the amount of current flowing through the solenoid.
Magnetising current is the electric current that is needed to create a magnetic field in a solenoid. It is also known as the excitation current.
The magnetising current in a solenoid can be calculated using the formula I = B x L x N / μ, where I is the current, B is the magnetic field strength, L is the length of the solenoid, N is the number of turns in the solenoid, and μ is the permeability of the material inside the solenoid.
Magnetising current is important because it determines the strength of the magnetic field in a solenoid. By controlling the amount of current, the strength of the magnetic field can be adjusted, making solenoids useful in various applications such as electromagnets, relays, and speakers.