- #1
dnt
- 238
- 0
Homework Statement
limit as x-> -oo of x+(x^2+3)^(1/2) (square root)
Homework Equations
n/a
The Attempt at a Solution
i first multiplied the top and bottom (which is just 1) by the conjugate to get:
-3
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[x - (x^2+3)^(1/2)]
then i divided by x on top and bottom to get:
-3/x
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[x/x - (1 + 3/x2)^(1/2)]
but now what do i do? the top goes to 0 but the bottom also goes to 0 (because its 1 - (1+0)^(1/2)). but the answer is suppose to be 0.
0/0 isn't 0. can someone point me in the right direction? thanks.