- #1
oceanflavored22
- 5
- 0
i'm doing extra problems in my textbook but one of them baffles me...
a hiker shouts toward a vertical cliff 685 m away. the echo is heard 4 s later
what is the speed of sound of the hiker's voice in air?
i know to calculate this you do velocity=distance/time.
and i did velocity=685/4 and got 171.
but in the answers, the book says that you have to do velocity=685/2
i don't know how they got 2 s, when the question clearly states it's 4.
is it just a typo? or do you have to halve the time when it's air?
thanks for anyone who can help me with this conundum
a hiker shouts toward a vertical cliff 685 m away. the echo is heard 4 s later
what is the speed of sound of the hiker's voice in air?
i know to calculate this you do velocity=distance/time.
and i did velocity=685/4 and got 171.
but in the answers, the book says that you have to do velocity=685/2
i don't know how they got 2 s, when the question clearly states it's 4.
is it just a typo? or do you have to halve the time when it's air?
thanks for anyone who can help me with this conundum