What Is the Tension in Cable A After Cord B Is Cut?

[pconn5]

Not really sure if this is where this should be but oh well.

Homework Statement

Image attached.

It is given that:

b = 200 mm
mass = 6 kg

Find the tension in cable A immediately after cord B is cut.

Homework Equations

Moment = I*alpha + m*a*d
F = ma?

The Attempt at a Solution

I tried to do
Moment about A = I*alpha (second part is zero?) , so 9.81*6*.1 = 1/6*6*2*.2^2*alpha

I then solved for alpha.

And plugged it into:
Moment about G(center) = I*alpha, but this is wrong and I don't really understand why to be honest with you. It trips me up when the forces are not perpendicular to the center for some reason.

The final answer is T = 23.5 N.

Thanks.

 

[KataKoniK]

Hello there,

Thank you for posting your question in this forum. I am happy to help you find the tension in cable A after cord B is cut.

To solve this problem, we need to use the equation F = ma, where F is the net force acting on the object, m is the mass of the object, and a is the acceleration of the object. In this case, we are interested in finding the tension in cable A, which is the net force acting on the object.

First, let's consider the forces acting on the object before cord B is cut. We have the weight of the object, which is equal to its mass (6 kg) multiplied by the acceleration due to gravity (9.81 m/s^2). This results in a force of 58.86 N acting downwards.

Next, let's consider the forces acting on the object after cord B is cut. We still have the weight of the object acting downwards, but now we also have the tension in cable A acting upwards. This tension is the net force acting on the object, since there are no other forces acting on the object in the vertical direction.

Now, we can set up the equation F = ma and solve for the tension in cable A. We know that the mass of the object is 6 kg and the acceleration is unknown, so we can rewrite the equation as T = 6a. We also know that the net force acting on the object is equal to the weight of the object (58.86 N), so we can set up the equation T = 58.86 N.

Solving for a, we get a = 58.86/6 = 9.81 m/s^2. This is the acceleration of the object after cord B is cut.

Finally, we can plug this value of acceleration into our equation T = 6a to find the tension in cable A. This results in T = 6(9.81) = 58.86 N. This is the final answer for the tension in cable A immediately after cord B is cut.

I hope this explanation helps you understand the problem better. If you have any other questions, please feel free to ask. Good luck with your studies!