- #1
spursfan2110
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Hey, I'm just a tad confused about tension and how it works...
Two blocks m1 (11 kg) and m2 (18 kg) are connected by strings, as shown in the below. String 2 breaks when T2 = 4.9033 N. Find T1 when string 2 breaks.
Answer in units of N. (Blocks are on a flat surface, not hanging)
m1----(T2)-----m2----(T1)---->
F = ma
Not sure if any others are necessary, I don't believe so. Friction not included in this problem.
Before the string snaps, if T2 = 4.9033 N, at that point, the acceleration of m1 = T2/m1 = .44575454545 m/s/s. I assume acceleration across the whole system would be the same, making the T1 = (18 kg + 11 kg)(.445754545 m/s/s), but I am completely stuck on what happens after the string breaks...does the acceleration remain the same and make T1 = .445754545 m/s/s * 18 kg = 8.02358 N?
Also, its my first time here, did I include enough relevant info in my post? Any feedback greatly appreciated, thanks!
Homework Statement
Two blocks m1 (11 kg) and m2 (18 kg) are connected by strings, as shown in the below. String 2 breaks when T2 = 4.9033 N. Find T1 when string 2 breaks.
Answer in units of N. (Blocks are on a flat surface, not hanging)
m1----(T2)-----m2----(T1)---->
Homework Equations
F = ma
Not sure if any others are necessary, I don't believe so. Friction not included in this problem.
The Attempt at a Solution
Before the string snaps, if T2 = 4.9033 N, at that point, the acceleration of m1 = T2/m1 = .44575454545 m/s/s. I assume acceleration across the whole system would be the same, making the T1 = (18 kg + 11 kg)(.445754545 m/s/s), but I am completely stuck on what happens after the string breaks...does the acceleration remain the same and make T1 = .445754545 m/s/s * 18 kg = 8.02358 N?
Also, its my first time here, did I include enough relevant info in my post? Any feedback greatly appreciated, thanks!
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