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JeweliaHeart
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Homework Statement
For the reaction: A + B ↔ C + D
6.0 moles of A and 5.0 moles of B are mixed together in a suitable container. When equilibrium is reached, 4.0 moles of C are produced.
The equilibrium constant for this reaction is:
a. K = 1/8
b. K = 8
c. K = 30/16
d. K = 16/30
Homework Equations
K=[C][D]/[A]
The Attempt at a Solution
I set up the problem like this:
Initial Concentrations: [A] 6/x 5/x [C] 0 [D] 0
Change in Concentrations: [A] -4/x -4/x [C] +4/x [D] 0
Equlibirum Concentrations: [A] 2/x 1/x [C] 4/x [D] 0
I assigned the variables x myself:
x= volume of container
The reason I put 0 for D's concentration is b/c the problem did not say any amount of D was formed.
Therefore the equilibrium expression should look like this:
[4/x]/[2/x^2]
which further equates to 2x. I don't where I messed up or how to solve this. Any help would be appreciated. Thanks.