Which Equation Correctly Represents the Planck Distribution?

In summary, the conversation addresses an equation that is ambiguous and incorrectly written. The correct reading of the equation is e^(hf/kT) - 1 and it is likely related to the Planck distribution. The additional bracket [] may be present because it is part of a larger equation.
  • #1
Mechatron
38
0
Is this equation equal to:

(e^(hf/kT)) - 1

or

e^( (hf/kT) - 1 )

http://s29.postimg.org/le6iqy3rb/exp.png
 
Last edited by a moderator:
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  • #2
The former.
 
  • #3
Mechatron said:
Is this equation equal to:

(e^(hf/kT)) - 1

or

e^( (hf/kT) - 1 )

http://s29.postimg.org/le6iqy3rb/exp.png
First off, what you wrote is NOT an equation. An equation always has an = symbol in it.

The image in the link is [exp(hf/kT) - 1].

What you have written is ambiguous, as what you probably meant is this:
$$e^{\frac{hf}{kT} - 1}$$

What you actually wrote, though, is this:
$$e^{\frac{hf}{k}T - 1}$$

The brackets - [] - around the entire expression are unnecessary.
 
Last edited by a moderator:
  • #4
Mark44 said:
First off, what you wrote is NOT an equation. An equation always has an = symbol in it.

The image in the link is [exp(hf/kT) - 1].

What you have written is ambiguous, as what you probably meant is this:
$$e^{\frac{hf}{kT} - 1}$$

What you actually wrote, though, is this:
$$e^{\frac{hf}{k}T - 1}$$

The brackets - [] - around the entire expression are unnecessary.
Why did you put the -1 in the exponential? The parenthesis limit the argument of exp to hf/kT.

My guess is that Mechatron did not write that himself, but saw it in a book. It's most probably related to the Planck distribution (blackbody radiation). As economicsnerd said, the correct reading is
$$
e^{\beta h f} - 1 \mbox{ where } \beta = \frac{1}{kT}
$$
The additional bracket [] might be there because it is part of a greater equation.
 
  • #5
Im sorry to be off topic but I'm using a i device and i can't see (what i think to be) mathematical symbols that are in this thread... They appear as dollar signs and other randoms, i was wondering if maybe I'm short of additional download or setting adjustments. All help is highly appreciated
 
  • #6
DrClaude said:
Why did you put the -1 in the exponential? The parenthesis limit the argument of exp to hf/kT.
The posted image, which doesn't have the -1 term, doesn't match the expressions in the first post. In the first post Mechatron asks about these expressions:
(e^(hf/kT)) - 1

and

e^( (hf/kT) - 1 )

In any case, this is moot, as Mechatron has been banned from PF.

DrClaude said:
My guess is that Mechatron did not write that himself, but saw it in a book. It's most probably related to the Planck distribution (blackbody radiation). As economicsnerd said, the correct reading is
$$
e^{\beta h f} - 1 \mbox{ where } \beta = \frac{1}{kT}
$$
The additional bracket [] might be there because it is part of a greater equation.
 

FAQ: Which Equation Correctly Represents the Planck Distribution?

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