- #1
Kalimaa23
- 279
- 0
Greetings,
I found a puzzling reference in my EP-course, that basically says :
"Gluon cary a dual charge, one colour and one anticolour. This means one can have 3²=9 combinations."
So far, so good. But then :
"We have to substract one colourless combination. This leaves us with 8 gluons."
Huh? Why one colourless combination? I can see three :
Blue/Antiblue
Green/Antigreen
Red/Antired
Which would leave us with 6 gluons, which is obviouly wrong. Can anyone explain this to me?
Thanks in advance,
Dimi
I found a puzzling reference in my EP-course, that basically says :
"Gluon cary a dual charge, one colour and one anticolour. This means one can have 3²=9 combinations."
So far, so good. But then :
"We have to substract one colourless combination. This leaves us with 8 gluons."
Huh? Why one colourless combination? I can see three :
Blue/Antiblue
Green/Antigreen
Red/Antired
Which would leave us with 6 gluons, which is obviouly wrong. Can anyone explain this to me?
Thanks in advance,
Dimi