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Can anyone explain to me why gravity would not be a significant force on the 'surface' of a proton or neutron? A quick calculation shows that the acceleration of a neutron toward another neutron or a proton separated by less than the radius of a neutron, is very large (compared to the radius of the neutron). The acceleration is several orders of magnitude greater than the radius of the neutron [itex]/ sec^{2}[/itex]:
[tex]G = 6.67 \times 10^{-11} Nm^2 /kg^{2}[/tex]
1) diameter of nucleus of H is ~ [itex]10^{-15} m [/itex]
radius of nucleus is: [itex]5 \times 10^{-16} m[/itex]
2) mass nucleus of H is [itex]1.66 \times 10^{-27} kg.[/itex]
3) gravitational force and acceleration between two protons in He nucleus is:
[tex]F = GmM/r^2[/tex]
[tex]F = 6.67 \times 10^{-11} \times (1.66 \times 10^{-27})^2 \div (5 \times 10^{-16})^2[/tex]
[tex]F = .735 \times 10^{(-65+32)}[/tex]
[tex]F = 7.35 \times 10^{-34} N [/tex]
[tex]F = m a[/tex]
[tex]a = F / m[/tex]
[tex]a = 7.35 \times 10^{-34} \div 1.66 \times 10^{-27}[/tex]
[tex]a = 4.43 \times 10^{-7} m/sec^2[/tex]
Since the radius of the proton is ~ [itex]10^{-15} m,[/itex] this seems like a significant acceleration, or am I missing something?
Andrew Mason
[tex]G = 6.67 \times 10^{-11} Nm^2 /kg^{2}[/tex]
1) diameter of nucleus of H is ~ [itex]10^{-15} m [/itex]
radius of nucleus is: [itex]5 \times 10^{-16} m[/itex]
2) mass nucleus of H is [itex]1.66 \times 10^{-27} kg.[/itex]
3) gravitational force and acceleration between two protons in He nucleus is:
[tex]F = GmM/r^2[/tex]
[tex]F = 6.67 \times 10^{-11} \times (1.66 \times 10^{-27})^2 \div (5 \times 10^{-16})^2[/tex]
[tex]F = .735 \times 10^{(-65+32)}[/tex]
[tex]F = 7.35 \times 10^{-34} N [/tex]
[tex]F = m a[/tex]
[tex]a = F / m[/tex]
[tex]a = 7.35 \times 10^{-34} \div 1.66 \times 10^{-27}[/tex]
[tex]a = 4.43 \times 10^{-7} m/sec^2[/tex]
Since the radius of the proton is ~ [itex]10^{-15} m,[/itex] this seems like a significant acceleration, or am I missing something?
Andrew Mason