- #1
cesiumfrog
- 2,010
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(Reviving an old thread based on a recent request by "mr.smartass#1")
A sophisticated answer has to do with the notion that symmetries give rise to conserved quantities. The mathematical expression of this relationship is named Noether's theorem. In this case, the fact that the laws of physics are the same, from one day to another, necessarily implies conservation of a quantity which just turns out to be quadratic in velocity.
This is "deep" in the sense that Noether's theorem works in everything from general relativity to quantum field theory. The downside is that it needs you to start by supplying the Lagrangian. For somebody unfamiliar with this, it is going to be difficult to motivate the particular form of the Lagrangian (we can't just say T-V as that would be circular). You could derive it from Newton's laws (by following a proof of the Euler-Lagrange equations) but this seems excessively convoluted.
I think the simplest answer is just, it is a mathematical fact that [itex]\Delta (\frac 1 2 m\,v^2) = ma\, \Delta x[/itex]. This equation simply says that the change-in-KE (the left hand side) is equal to the Work (the name given to the right hand side, which can also be written as [itex]F\ \Delta x[/itex] because of F=ma, so the work just measures how forcefully and how far you push). This equation is usually known in the familiar form "v2-u2=2as". The proof is basic calculus: [itex]\frac {\delta (\frac 1 2 m\,{\dot x}^2)} {\delta x} = m \frac {\delta (\frac 1 2 {\dot x}^2)} {\delta \dot x} \frac {\delta \dot x} {\delta t} \frac {\delta t} {\delta x} = m\ \dot x \ddot x \frac 1 {\dot x}[/itex] (using the chain rule). If there are no external forces doing work on the system then, because the internal forces are balanced (by Newton's 3rd law), this equation tells us that any internal redistributions of v2 must also stay balanced (so that the total is conserved). Something like that?
A sophisticated answer has to do with the notion that symmetries give rise to conserved quantities. The mathematical expression of this relationship is named Noether's theorem. In this case, the fact that the laws of physics are the same, from one day to another, necessarily implies conservation of a quantity which just turns out to be quadratic in velocity.
This is "deep" in the sense that Noether's theorem works in everything from general relativity to quantum field theory. The downside is that it needs you to start by supplying the Lagrangian. For somebody unfamiliar with this, it is going to be difficult to motivate the particular form of the Lagrangian (we can't just say T-V as that would be circular). You could derive it from Newton's laws (by following a proof of the Euler-Lagrange equations) but this seems excessively convoluted.
I think the simplest answer is just, it is a mathematical fact that [itex]\Delta (\frac 1 2 m\,v^2) = ma\, \Delta x[/itex]. This equation simply says that the change-in-KE (the left hand side) is equal to the Work (the name given to the right hand side, which can also be written as [itex]F\ \Delta x[/itex] because of F=ma, so the work just measures how forcefully and how far you push). This equation is usually known in the familiar form "v2-u2=2as". The proof is basic calculus: [itex]\frac {\delta (\frac 1 2 m\,{\dot x}^2)} {\delta x} = m \frac {\delta (\frac 1 2 {\dot x}^2)} {\delta \dot x} \frac {\delta \dot x} {\delta t} \frac {\delta t} {\delta x} = m\ \dot x \ddot x \frac 1 {\dot x}[/itex] (using the chain rule). If there are no external forces doing work on the system then, because the internal forces are balanced (by Newton's 3rd law), this equation tells us that any internal redistributions of v2 must also stay balanced (so that the total is conserved). Something like that?