- #1
Luca_Mantani
- 36
- 1
Hi everyone,
I read this property of dimensional regularization, but i do not understand why it is so.
$$\int d^dp =0$$.
Actually looking for an answer i also saw that a general property of dim. reg. is
$$\int d^dp \, (p^2)^\alpha=0$$
for any value of ##\alpha##, so also for ##\alpha=0##. Do you have an explanation for this?
Thanks in advance.
I read this property of dimensional regularization, but i do not understand why it is so.
$$\int d^dp =0$$.
Actually looking for an answer i also saw that a general property of dim. reg. is
$$\int d^dp \, (p^2)^\alpha=0$$
for any value of ##\alpha##, so also for ##\alpha=0##. Do you have an explanation for this?
Thanks in advance.