Why no constant of integration for the integration factor?

In summary, when applying the usual formula for solving y'+py=q, the result of the indefinite integral to calculate u is without a constant. This is because adding a constant does not change the final result. For example, when solving dy/dx + y = x*exp(-x), the integral will result in exp(-x)*(x2/2 +C), but adding constants for the integration factor will result in exp(-x)*(C1x2 +C2), which is not the same thing.
  • #1
nomadreid
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In applying the usual formula for y'+py=q with u=e∫p and y=(∫uq +C)/u, the results of the indefinite integral to calculate u is without a constant. Why is this? The result is not the same.
For example, suppose I take the problem
dy/dx +y = x*exp(-x). Then, in the usual manner, I get a nice exp(-x)*(x2/2 +C). But if I were to put constants in for the integration factor, I get
exp(-x)*(C1x2 +C2)
which is not the same thing.
 
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  • #2
[tex] y' + py = q [/tex]
Define [itex]\displaystyle p = P' [/itex]
[tex] u = e^{\int p\ dx} [/tex]
[tex] = Pe^C \Rightarrow u = AP [/tex]
Then [itex]\displaystyle (yu)' = uq [/itex]
[tex] y = \frac{\int uq\ dx}{u} [/tex]
[tex] = \frac{\int APq\ dx}{AP} [/tex]
[tex] = \frac{A}{A}\frac{\int Pq\ dx}{P} [/tex]
So adding the constant doesn't change anything :)
 
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  • #3
Thanks, JHamm.
 

FAQ: Why no constant of integration for the integration factor?

Why is there no constant of integration for the integration factor?

The integration factor is used to solve differential equations, which are equations that involve derivatives. When using the integration factor, the constant of integration is not necessary because it cancels out during the integration process.

Can the integration factor be used without a constant of integration?

Yes, the integration factor can be used without a constant of integration. This is because the constant of integration is not needed for the integration process to work effectively.

How does the integration factor eliminate the need for a constant of integration?

The integration factor works by multiplying the original differential equation, which contains the constant of integration, by a specific function. This function is chosen in such a way that it cancels out the constant of integration during integration, thus eliminating its need.

Is the integration factor always used to eliminate the constant of integration?

No, the integration factor is not always necessary to eliminate the constant of integration. It is only used in specific cases, such as when solving linear first-order differential equations, where it simplifies the integration process.

Can the integration factor be used in all types of differential equations?

No, the integration factor is not applicable to all types of differential equations. It is most commonly used in linear first-order differential equations, but may not be effective in other types of equations.

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