- #1
papacy
- 5
- 0
if p is prime and n is natural number, show that (p-n+1) . (p-2)! + n–1 =0 (mod p)
i think i have to show that (p-n+1) . (p-2)! = 0 (mod p) and n – 1 =0 (mod p)
using Wilson theorem
(p-1)!=-1(p)
i think i have to show that (p-n+1) . (p-2)! = 0 (mod p) and n – 1 =0 (mod p)
using Wilson theorem
(p-1)!=-1(p)
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