- #1
essie52
- 10
- 0
Could someone please help?
The question reads:
For which real numbers "k" is the zero state a stable equilibrium of the dynamic system (vector(x))(t+1)=A(vector(x))(t)?
A= [0.1 k ## 0.3 0.3] --> a 2 x 2 matrix with ## separating the two rows.
So, my thought is I need to find the eigenvalues. In order to do this I calculated the characteristic polynomial as:
x^2 - 0.4x + 0.03 - 0.3k = 0 with x representing eigenvalues
Using the quadratic formula I found that the (real) eigenvalues are (2 +/- (sqrt(1+30k)))/10 and for the zero state to be in stable equilibrium sqrt(1+30k) < 8. Hence, k < 21/10 (for stable equilibrium).
My question is how do I figure out the values for k if the eigenvalues are complex?
Do I solve the inequality 2 +/- (sqrt(-1-30k)) < 8?
Thanks!
The question reads:
For which real numbers "k" is the zero state a stable equilibrium of the dynamic system (vector(x))(t+1)=A(vector(x))(t)?
A= [0.1 k ## 0.3 0.3] --> a 2 x 2 matrix with ## separating the two rows.
So, my thought is I need to find the eigenvalues. In order to do this I calculated the characteristic polynomial as:
x^2 - 0.4x + 0.03 - 0.3k = 0 with x representing eigenvalues
Using the quadratic formula I found that the (real) eigenvalues are (2 +/- (sqrt(1+30k)))/10 and for the zero state to be in stable equilibrium sqrt(1+30k) < 8. Hence, k < 21/10 (for stable equilibrium).
My question is how do I figure out the values for k if the eigenvalues are complex?
Do I solve the inequality 2 +/- (sqrt(-1-30k)) < 8?
Thanks!