Electric Field at a Point on the Axis of a Charged Disk?

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The discussion focuses on calculating the electric field at a point on the axis of a charged disk with a specific surface charge density equation. The surface charge density, sigma, is defined as sigma = (sqrt(r^2 + 961)) x 10^-6 C/m², where r is the radial distance in meters. Participants seek clarification on the integration process needed to find the electric field, particularly regarding the limits of integration and the interpretation of the charge density equation. The correct interpretation of the equation is confirmed to be the square root of (r squared + 961) multiplied by 10^-6. The thread emphasizes the importance of accurately understanding the equation to proceed with the calculations.
smballer23
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Homework Statement


A flat, circular annulus of radius 7 m with a hole in the center of radius 2 m is charged on one surface such that the surface charge density varies with the radial distance from the center of the disk by the equation sigma= (r2 + 961)1/2 x 10-6, where is in C/m2 and r is in meters.

Find the magnitude of the electric field at a point on the axis of the disk, a distance 31 m away from the center of the disk.

Homework Equations

disk8.gif

The Attempt at a Solution



Do I combine the equations and integrate from 2 to 7? I am lost...
 
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You write: "sigma= (r2 + 961)1/2 x 10-6". Please clarify. Is that r2 or r2? Is 961 in units of meters or meters2? Is that (r2 + 961) x 1/(2 x 10-6), or is it (r2 + 961) x (1/2) x 2 x 10 - 6? Or something else?
 
r2 is r squared. 961 is meters.
It is (sqrt(r squared + 961))e-6.
 

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