What is Laurent series: Definition and 162 Discussions

In mathematics, the Laurent series of a complex function f(z) is a representation of that function as a power series which includes terms of negative degree. It may be used to express complex functions in cases where a Taylor series expansion cannot be applied. The Laurent series was named after and first published by Pierre Alphonse Laurent in 1843. Karl Weierstrass may have discovered it first in a paper written in 1841, but it was not published until after his death.The Laurent series for a complex function f(z) about a point c is given by




f
(
z
)
=



n
=








a

n


(
z

c

)

n


,


{\displaystyle f(z)=\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n},}
where an and c are constants, with an defined by a line integral that generalizes Cauchy's integral formula:





a

n


=


1

2
π
i






γ





f
(
z
)


(
z

c

)

n
+
1






d
z
.


{\displaystyle a_{n}={\frac {1}{2\pi i}}\oint _{\gamma }{\frac {f(z)}{(z-c)^{n+1}}}\,dz.}
The path of integration



γ


{\displaystyle \gamma }
is counterclockwise around a Jordan curve enclosing c and lying in an annulus A in which



f
(
z
)


{\displaystyle f(z)}
is holomorphic (analytic). The expansion for



f
(
z
)


{\displaystyle f(z)}
will then be valid anywhere inside the annulus. The annulus is shown in red in the figure on the right, along with an example of a suitable path of integration labeled



γ


{\displaystyle \gamma }
. If we take



γ


{\displaystyle \gamma }
to be a circle




|

z

c

|

=
ϱ


{\displaystyle |z-c|=\varrho }
, where



r
<
ϱ
<
R


{\displaystyle r<\varrho <R}
, this just amounts
to computing the complex Fourier coefficients of the restriction of



f


{\displaystyle f}
to



γ


{\displaystyle \gamma }
. The fact that these
integrals are unchanged by a deformation of the contour



γ


{\displaystyle \gamma }
is an immediate consequence of Green's theorem.
One may also obtain the Laurent series for a complex function f(z) at



z
=



{\displaystyle z=\infty }
. However, this is the same as when



R




{\displaystyle R\rightarrow \infty }
(see the example below).
In practice, the above integral formula may not offer the most practical method for computing the coefficients





a

n




{\displaystyle a_{n}}
for a given function



f
(
z
)


{\displaystyle f(z)}
; instead, one often pieces together the Laurent series by combining known Taylor expansions. Because the Laurent expansion of a function is unique whenever
it exists, any expression of this form that actually equals the given function




f
(
z
)


{\displaystyle f(z)}
in some annulus must actually be the Laurent expansion of



f
(
z
)


{\displaystyle f(z)}
.

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  1. E

    Why use a laurent series in complex analysis?

    In complex analysis, what exactly is the purpuse of the luarent series, i mean, i know that it apporximates the function like a taylor series, an if the function is analytic in the whole domain it simplifies into a taylor series. But i fail to see its purpose - what does it do that the taylor...
  2. C

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  3. M

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    Homework Statement Could anyone help me with Laurent series? I do not understand it at all even though the book has several examples. And here is one with my comments Find the Laurent series of \frac{1}{(z-1)(z-2)} a in the region abs(z) < 1 b in the region 1< abs(z) < 2 c in the...
  4. T

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  5. J

    Finding Laurent Series of 1/sinh(z) Up to z^5 Term

    Homework Statement Find the Laurent series about 0 of 1/sinh up to (and including 0) the z5 term Homework Equations The Attempt at a Solution Since 1/sinh is equal to (1/z) * (1/(1+(z^2/3!)+(z^4/5!)+(z^6/7!)+...)) So if we work on the second term by dividing 1 by denominator and multiply...
  6. J

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  7. M

    Laurent series throwing away terms

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  8. D

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  9. F

    Partial Fractions using Laurent Series

    We were discussing them in my math methods class today however I'm not really sure how the idea works. Does anyone know of any online references that might be of some help? Google wasn't much help for me =/
  10. Z

    Why NO multiple Laurent series ?

    why NO multiple Laurent series ?? why are ther Taylor series in several variables (x_{1} , x_{2} ,..., x_{n} but there are NO Laurent series in several variables ? why nobody has defined this series , or why they do not appear anywhere ? i think there are PADE APPROXIMANTS in serveral...
  11. R

    All Laurent series expansion around 1.

    Homework Statement Question is= Find all Laurent series expansion of f(z)=z^4/(3+z^2) around 1. I will be very very thankful if someone can help me to do this question. Homework Equations The Attempt at a Solution can I assume (z-1=u) here and change the function in terms of...
  12. N

    Areas in developing laurent series

    f(x)=\frac{-2}{z-1}+\frac{3}{z+2} our distance is from -2 till 1 we develop around 1 so our distances are 3 and zeo so our areas are 0<|z-1|<3 0<|z-1| 3>|z-1| but i was told to develop around 0<|z-1|<1 there is no such area ?
  13. N

    What is the radius of convergence for Laurent series of the given function?

    find the laurent series of f(x)=\frac{-2}{z-1}+\frac{3}{z+2} for 1<|z|<2 i was by my teacher that the radius of convergence is what smaller then the number which makes the denominator 0. if f(x)=\frac{1}{1-z} then the radius is 1 and because 1-1=0 so it is analitical on |z|<1 so...
  14. S

    Calculating a Laurent Series: 1/(z2(z+i))

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  15. G

    Find the Laurent Series for f(z)=1/(z(z-1)) Valid on 1<|z-1|<infinity

    Homework Statement Find the Laurent series for f(z)=1/(z(z-1)) valid on 1<|z-1|<infinity Homework Equations 1/(1+a)=1-a+a^2-a^3... where |a|<1 we are not supposed to use integrals for this problem The Attempt at a Solution I want 1/(z-1) to be in my final answer, so I have...
  16. D

    Hard Laurent series. A little lost.

    Homework Statement find the Laurent series for \frac{z+2}{z^{5}-8z^{2}} in 2<|z|<\infty Homework Equations The Attempt at a Solution Well, I factored out z^{5} in the denominator, which left me with a geometric sum (since |z|>2). I've come up with...
  17. B

    Finding Maclaurin & Laurent Series for f(z)

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  18. E

    How to calculate the Laurent series expansion of 1/(1-z)² in the region 1<|z|?

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  19. S

    Finding Laurent Series for Rational Functions with Partial Fractions

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  20. Z

    How Can We Calculate Coefficients in Multivariable Laurent Series?

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  21. M

    Laurent series: can calculate myself, just need a quick explanation how

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  22. M

    What is the difference between geometric series and laurent series?

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  23. W

    Laurent series expansion help

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  24. V

    Laurent Series expansion for the following function

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  25. V

    Laurent Series (non-homework) question

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  26. N

    Need Help With Laurent Series Struggles?

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  27. B

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  28. L

    Laurent series: addition and multiplication of series

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  29. L

    Laurent series (COMPLICATED, )

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  30. L

    Multiplication of Laurent Series

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  31. S

    Laurent Series for f(z): Computing Contour Integral

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  32. E

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  33. K

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  34. O

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  35. O

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  36. Q

    Finding Laurent Series for a Rational Function on an Annulus

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  37. A

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  38. W

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  39. A

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  40. C

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  41. N

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  42. K

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  43. M

    Find Laurent Series & Area of Convergence for f(z)

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  44. M

    Finding the Laurent Series for 1/(x+3) around x=2

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  45. Q

    Laurent series for f(z) = 1/(exp(z)-1)^2 ?

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  46. Q

    Confused about computing Laurent series

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  47. H

    C-R of Laurent Series

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  48. F

    Laurent Series and Partial Fractions: Exam Help Requested

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  49. E

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  50. F

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