Calculating electric charge from graph (capacitor)

In summary, the conversation is about finding the amount of electronic charge on a capacitor by integrating the functions from 0 to the time when it is fully charged. The initial voltage is given as 10 V and the capacity and resistance are 2*10^(-6) F and 1*10^6 Ω respectively. There is confusion about whether the capacitor is being charged or discharged.
  • #1
krisu334
1
0
Homework Statement
When charging a capacitor we obtained a graph of voltage in terms of time. From the graph, find the amount of electronic charge on the capacitor.
Relevant Equations
Initial voltage: 10 V
Capacity: 2*10^(-6) Fahr.
Resistance: 1*10^6 Ohm
Apparently, we need to integrate the functions from 0 to the time when it is fully charged. However, I integrated in terms of t so the soultion (according to a graph programme) should be around 236 Vs but I don’t see how this could help me.
 
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  • #2
Hello @krisu334 ,
:welcome: ##\ ##!​
What is the expected relationship between ##V## and ##t##?
 
  • #3
krisu334 said:
Homework Statement: When charging a capacitor we obtained a graph of voltage in terms of time. From the graph, find the amount of electronic charge on the capacitor.
Relevant Equations: Initial voltage: 10 V
Capacity: 2*10^(-6) Fahr.
Resistance: 1*10^6 Ohm

Apparently, we need to integrate the functions from 0 to the time when it is fully charged. However, I integrated in terms of t so the soultion (according to a graph programme) should be around 236 Vs but I don’t see how this could help me.
Hi @krisu334. In addition to @BvU ’s question:

Presumably V is the voltage across the capacitor. Are you charging or discharging? You say “Initial voltage: 10 V” which implies you are discharging. But you also say “from 0 to the time when it is fully charged” which implies charging.

Minor points, for information:
The unit of capacitance (not “capacity”) is the ‘farad’ (lower case), symbol ‘F’.
The unit of resistance is the ‘ohm’ (lower case), symbol ‘Ω’.
 
  • #4
Well, what is the status?
 

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