Converting from sin to cos appropriately with phasors

  • #1
wellmoisturizedfrog
3
1
TL;DR Summary
Difficulty understanding when to add pi/2 vs when to subtract pi/2.
My transmissions line class often features problems where the voltage is expressed as a sin, not a cos. Obviously a phase shift of pi/2 is sufficient to convert between the two. However, I have trouble understanding when adding pi/2 is appropriate as opposed to subtracting pi/2. As per my understanding, both should be sufficient to achieve the desired conversion, but my professor says otherwise. While I understand that the angle should reflect the position of the phasor in the complex domain, I still feel as though I am missing something. Could anyone offer a concrete clarification of this matter?
 
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  • #2
Can you be more specific? Note that:
$$\sin(x +\frac{\pi}2) = \cos(x)$$
 
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Likes sophiecentaur
  • #3
You might get better help if you post an actual problem, with full details, and ask that question. For any homework-type problem, you need to show as much of your own work as possible. There is a specific format for homework-type problems.
 
  • #4
wellmoisturizedfrog said:
I still feel as though I am missing something. Could anyone offer a concrete clarification of this matter?
##sin(\Theta - \frac{\pi}{2}) = -cos(\Theta)##
##sin(\Theta + \frac{\pi}{2}) = cos(\Theta)##
etc.

Can you explain a bit more about what you are unsure of?
 
  • #5
wellmoisturizedfrog said:
TL;DR Summary: Difficulty understanding when to add pi/2 vs when to subtract pi/2.

However, I have trouble understanding when adding pi/2 is appropriate as opposed to subtracting pi/2. As per my understanding, both should be sufficient to achieve the desired conversion, but my professor says otherwise.
One will convert sin() to cos(), the other will do the same, but will invert the signal, by the net phase shift of pi.
 
  • #6
wellmoisturizedfrog said:
TL;DR Summary: Difficulty understanding when to add pi/2 vs when to subtract pi/2.

but my professor says otherwise.
I wonder if he really said that or if you mis- interpreted him (i.e. just in one particular example). The 'timing of events (phases) can sometimes be very relevant but not always.
 

Related to Converting from sin to cos appropriately with phasors

1. How do you convert from sin to cos appropriately with phasors?

To convert from sin to cos appropriately with phasors, you can use the relationship between sine and cosine functions: sin(θ) = cos(θ - π/2). This means that to convert a sine function to a cosine function, you simply need to shift the phase by π/2 radians.

2. Why is it important to convert from sin to cos with phasors?

Converting from sin to cos with phasors is important in electrical engineering and other fields that deal with alternating current (AC) circuits. Phasors are used to represent the magnitude and phase angle of AC voltages and currents, and converting between sine and cosine functions allows for easier analysis and calculation of AC circuit parameters.

3. Can you provide an example of converting from sin to cos appropriately with phasors?

Sure! Let's say we have a sinusoidal voltage function v(t) = 10sin(ωt + 30°). To convert this to a cosine function with a phasor representation, we can use the relationship sin(θ) = cos(θ - π/2) to get v(t) = 10cos(ωt - 60°).

4. Are there any shortcuts or tricks for converting from sin to cos with phasors?

One shortcut for converting from sin to cos with phasors is to remember that the cosine function leads the sine function by π/2 radians. This means that you can simply subtract π/2 from the phase angle of the sine function to get the equivalent cosine function.

5. What are some common mistakes to avoid when converting from sin to cos appropriately with phasors?

One common mistake to avoid when converting from sin to cos with phasors is forgetting to adjust the phase angle appropriately. Remember that the cosine function leads the sine function by π/2 radians, so make sure to subtract π/2 from the phase angle of the sine function to get the correct cosine function.

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