Disk falling while rotating round a point

In summary, the disk of mass m and radius R falls from position (a) to position (b), with a horizontal orientation. The velocities and accelerations at position (b) can be calculated using the equations for moment of inertia, torque, energy, and centripetal acceleration. The angular velocity is given by ω = √(4g/3R), the COM's velocity is vcm = 2√(gR/3), the radial acceleration is a_rad = 4g/3, and the tangential acceleration is a_tan = 2g/3.
  • #1
Karol
1,380
22

Homework Statement


The disk of mass m and radius R is at position (a), upwards. it is free to rotate round point O on it's circumference.
If falls and reaches state (b), horizontal position.
What are the velocities and accelerations in position (b)

Homework Equations


Moment of inertia of a disk: ##I=\frac{1}{2}mR^2##
Torque of rigid body: ##M=I\alpha##
Energy of a rigid body: ##E=\frac{1}{2}I\omega^2##
Centripetal acceleration: ##a_{cen}=\frac{v^2}{R}=\omega^2 R##

The Attempt at a Solution


The angular velocity ω is from energy conservation:
$$mgR=mR^2\left( \frac{1}{2}+1 \right)\omega^2\; \rightarrow \omega^2=\frac{4g}{3R}$$
COM's velocity is ##v_{cm}=\omega R=\sqrt{\frac{4g}{3R}}R=2\sqrt{\frac{gR}{3}}##
The radial velocity from the circular motion:
$$a_{cen}=\omega^2 R=\frac{4g}{3}$$
Tangential acceleration is from the gravity:
$$M=I\alpha\rightarrow mgR=\frac{3}{2}mR^2\alpha\rightarrow\alpha=\frac{2g}{3R}$$
$$a_{tan}=R\alpha=\frac{2g}{3}$$
 

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  • #3
One typo... where you wrote radial velocity you meant radial acceleration.
 
  • #4
Thanks
 

Related to Disk falling while rotating round a point

1. What causes a disk to fall while rotating around a point?

The force of gravity is what causes a disk to fall while rotating around a point. The disk's weight and the centripetal force of the rotation both contribute to the downward motion.

2. How does the speed of rotation affect the disk's fall?

The faster the disk is rotating, the stronger the centripetal force will be, and the more likely it is to stay in its circular path. However, if the speed of rotation is too slow, the force of gravity will overpower the centripetal force and the disk will fall.

3. Can the shape or mass of the disk affect its fall while rotating?

Yes, the shape and mass of the disk can affect its fall while rotating. A disk with a larger mass will have a greater force of gravity acting on it, making it more likely to fall. The shape of the disk can also impact the distribution of weight and the centripetal force.

4. Is there a point at which the disk will stop falling and stay in its circular path?

Yes, there is a point at which the disk will stop falling and stay in its circular path. This is known as the equilibrium point, where the force of gravity and the centripetal force are balanced, allowing the disk to maintain a constant circular motion.

5. What other factors can influence the disk's fall while rotating?

Other factors that can influence the disk's fall while rotating include air resistance, friction, and the surface on which the disk is rotating. These external forces can affect the balance between the centripetal force and gravity, causing the disk to fall or stay in its circular path.

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